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andrew-mc [135]
3 years ago
5

Please help! geometry question!

Mathematics
1 answer:
Margaret [11]3 years ago
6 0

Answer:

Step-by-step explanation:

∠B=∠C (isosceles triangle)

so ⊥ AD bisects BC.

or BD=CD

2x-15=x+7

2x-x=7+15

x=22

AD=4x-6=22×4-6=82

DC=22+7=29

AC=\sqrt{(82^2+29^2)} =\sqrt{6724+841} =\sqrt{7565} \approx 86.977 \approx 86.98

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3 years ago
It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How
omeli [17]

Number of child tickets bought is 20

<h3><u>Solution:</u></h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

<em>Number of child tickets bought + number of adult tickets bought = 110</em>

c + a = 110 ----- eqn 1

<em><u>Also we can frame a equation as:</u></em>

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

c \times 5 + a \times 8 = 820

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c  ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

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