Answer:
Erosion of undersea stalagmites and stalactites. Erosion of the face of a cliff by waves. Rising of magma from the seafloor.
Explanation:
Answer:
a colloid and a solution
Explanation:
When solute particles completely dissolve in a solvent, a true solution is formed. The solute particles in this case are so little that they can not be seen with naked eyes. A true solution does not scatter rays of light.
In a false solution, the solute particles are larger than the solute particles in true solutions but are not large enough to be seen with naked eyes. False solutions scatter rays of light. False solutions are also called colloids.
The major difference between a solution and a colloid is that colloids scatter light rays (Tyndall effect) while a true solution does not scatter light rays.
Answer:
Explanation:
SO; If we assume that:
P should be the diffusion of oxygen towards the surface ; &
Q should be the diffusion of carbondioxide away from the surface.
Then the total molar flux of oxygen is illustrated by
:

where;
r is the radial distance from the center of the carbon particle.
Since ;
; we have:

The system is not steady state and the molar flux is not independent of r because the area of mass transfer
is not a constant term.
Therefore, using quasi steady state assumption, the mass transfer rate
is assumed to be independent of r at any instant of time.

= constant
The oxygen concentration at the surface of the coal particle
will be calculated from the reaction at the surface.
The mole fraction of oxygen at a location far from pellet is 1.
Thus, separating the variables and integrating result into the following:




The mole of oxygen arrived at the carbon surface is equal to the mole of oxygen consumed by the chemical reaction.







Obtaining the total gas concentration from the ideal gas law; we have the following:
where;
R= 

The steady state
molar consumption rate is:



You multiply 32 by 2, since there are two hydrogens in every water molecule.
Answer:
62.98 % of the sample of hydrate is water
Explanation:
Step 1: Data given
Mass of the sample of a hydrate of sodium carbonate (Na2CO3) = 2.026 grams
After heating, the mass of the sample is 0.750 g
Molar mass H2O = 18.02 g/mol
Step 2: Calculate mass of water
Mass water = mass of hydrate - mass of sample after heating
Mass water = 2.026 grams - 0.750 grams
Mass water = 1.276 grams
Step 3: Calculate mass % percent of water
Mass % of water = (mass of water / total mass hydrate) * 100 %
Mass % of water = (1.276 grams / 2.026 grams) *100 %
Mass % of water = 62.98 %
62.98 % of the sample of hydrate is water