Answer:
Second Ionization energy
Explanation:
Let us write the reaction equation properly:
Ca⁺ → Ca²⁺ + e⁻
In the reaction above, we see that calcium goes from a single charge to being doubly charged by losing an electron.
Different atoms binds their valence electrons with different amount of energy. We must supply enough energy to remove the most losely held electrons in an atom. This amount of energy required is called the ionization energy.
The first ionization energy removes the outermost electron and makes the atom to become an ion.
The reaction where one component splits into two or more is a decomposition reaction.
t doesn't represent the concentration of AgCl dissolved in water because we assume that AgCl dissociates into Ag+ ions and Cl- ions when it dissolves in water. It can't represent the amount of solid AgCl in the system because the equilibrium is not affected by the amount of excess solid added to the system.
Answer:
Entropy is a measurement of how much the atoms in a substance are free to spread out, move around, and arrange themselves in random ways
Answer:
Explanation:
<u>1) Rate law, at a given temperature:</u>
- Since all the data are obtained at the same temperature, the equilibrium constant is the same.
- Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:
r = K [A]ᵃ [B]ᵇ
<u>2) Use the data from the table</u>
- Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:
r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s
r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s
Divide r₂ by r₁: [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0
- Use the first and second set of data to find the exponent a:
r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s
r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s
Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]
2ᵃ = 2 ⇒ a = 1
<u>3) Write the rate law</u>
This means, that the rate is independent of reactant B and is of first order respect reactant A.
<u>4) Use any set of data to find K</u>
With the first set of data
- r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹
Result: the rate constant is K = 0.167 s⁻¹
