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Rufina [12.5K]
2 years ago
13

HELPPPPP

Chemistry
1 answer:
Kobotan [32]2 years ago
7 0

We have already been introduced to solutions. Several chapters ago molarity (M) was introduced. Molarity is measured in moles per liter, or mol/L. A 0.30 M NaCl solution means that there is 0.30 mol NaCl in every liter of solution.

Often chemists have to make solutions; so, doing the calculations necessary to make a certain amount of solution become second nature.

For example:

Make 250 mL of a 0.30 M NaCl solution.

To make the solution we need to calculate the amount of NaCl to dissolve to make 250 mL of solution.

start with 250 mL

The solution is made by adding 4.38 g NaCl to a 250-mL volumetric flask. About 100 mL of water are added and when all the NaCl dissolves water is added up to the line on the volumetric flask.

But molarity is not the only unit we use; so, we need to be able to convert between different units...

Common units of concentration include

<==> <==><==>

% wt.

% vol

molarity (M)

molality (m)

mol fraction

That is, the mol fraction of "a" is the number of moles of "a" present divided by the total number of moles of material in the solution (including the solvent).

There is no simple formula for converting from one concentration unit to the next. In general the first step is to pick a convenient sample size. Then work to change each part of the concentration unit to the new unit. Do not try to do the conversion all at once.

For example,

HCl comes in bottles marked 37 % HCl by weight. The density of the solution is 1.200 g/cm-1. What is the molarity of the solution?

A conveneint sample size is 100 g of solution; convenient because 100 g x 37% = 37 g HCl.

This is the key...you must know the definitions for all the concentration terms

First, convert number of grams of HCl in your sample to number of moles in your sample (the 100 g of solution).

Second, convert g of solution to L of solution.

Third, divide moles by liters and you have molarity.

What is the molality of this solution?

Going from M to m. Since the concentration is in M a convenient sample size is 1 L.

OK, so the first conversion is not a conversion...there are 12 mol HCl present in 1 L of solution.

The second conversion is not as easy as it first appears. Let's use the density of the solution to perform a conversion from volume to mass.

This is NOT the mass that is used in molality. We just determined the mass of the solution; molality uses the mass of the SOLVENT!

The solution is made of a solvent and a solute. So, the mass of solvent can be found by subtracting the mass of the solute from the mass of the solution.

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Dafna1 [17]

Explanation:

Homogeneous catalysis refers to catalytic reactions where the catalyst is in the same phase as the reactants.

Heterogeneous catalysis is the type of catalysis where the phase of the catalyst differs from the phase of the reactants or products.

Platinum is used to catalyze the hydrogenation of ethylene:

H2(g)+CH2CH2(g)− ⟶ Pt(s) CH3CH3(g)

In this reaction, the platinum is in the solid state. While the other species (reactants and products) are in their gaseous state.

This reaction is Heterogenous catalysis.

Chlorofluorocarbons (CFCs) catalyze the conversion of ozone (O3O3) to oxygen gas (O2O2):

2O3(g)− ⟶ CFC(g) 3O2(g)

The catalyst is in the same gaseous state as the reactant and product.

This reaction is Homogenous catalysis.

Magnesium catalyzes the disproportionation of hydrogen peroxide to produce water and oxygen:

2H2O2(aq)− ⟶ Mg(s) 2H2O(l) + O2(g)

In this reaction, the Magnesium is in the solid state. While the other species (reactants and products) are in their gaseous state.

This reaction is Heterogenous catalysis.

4 0
4 years ago
Why are some metals such as copper and aluminium not magnetic​
ioda

Answer:i dont know

Explanation:

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K

8 0
3 years ago
Ionic compounds can conduct electricity when dissolved in water or melted, because
emmainna [20.7K]
I believe the correct response would be A. The ions once dissolved in the solution are free to move
5 0
4 years ago
Read 2 more answers
If 24.3 g of NO and 13.8 g of O₂ are used to form NO₂, how many moles of excess reactant will be left over?2 NO (g) + O₂ (g) → 2
zhuklara [117]

Explanation:

2 NO (g) + O₂ (g) ----> 2 NO₂ (g)

24.3 g of NO are reacting with 13.8 g of O₂. First we can convert the mass of theses samples into moles using their molar masses.

molar mass of O = 16.00 g/mol

molar mass of N = 14.01 g/mol

molar mass of NO = 16.00 g/mol + 14.01 g/mol

molar mass of NO = 30.01 g/mol

molar mass of O₂ = 2 * 16.00 g/mol

molar mass of O₂ = 32.00 g/mol

moles of NO = 24.3 g * 1 mol/(30.01 g)

moles of NO = 0.810 moles

moles of O₂ = 13.8 g * 1 mol/(32.00 g)

moles of O₂ = 0.431 moles

Now, to determine the limiting reactant or the excess reactant we can find the number of moles of O₂ that will react with 0.810 moles of NO and the number of moles of NO that will react with 0.431 moles of O₂.

According to the coefficients of the reaction 2 moles of NO will react with 1 mol of O₂. Let's use that relationship to find the limiting reagent.

2 moles of NO = 1 mol of O₂

moles of O₂ = 0.810 moles of NO * 1 mol of O₂/(2 moles of NO)

moles of O₂ = 0.405 moles

moles of NO = 0.431 moles of O₂ * 2 moles of NO/(1 mol of O₂)

moles of NO = 0.862 moles

We found that we need 0.405 moles of O₂ to completely react with 0.810 moles of NO. Or, we need 0.862 moles of NO to completely react with ours 0.431 moles of NO.

We can say that NO is limiting our reaction and O₂ is in excess.

Only 0.405 moles of O₂ will react with 0.810 moles of NO. But we had 0.431 moles of it. Let's find the excess.

Excess of O₂ = 0.431 moles - 0.405 moles

Excess of O₂ = 0.026 moles

Answer: 0.026 moles is the number of moles of oxygen that will be left over.

4 0
1 year ago
Find the volume of 0.100M hydrochloric acid necessary to react completely with 1.51g Al(OH)3.
shtirl [24]
Reaction equation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
Moles of Al(OH)₃:
moles = mass/Mr
= 1.51 / (27 + 17 x 3)
= 0.019
Molar ratio Al(OH)₃ : HCl = 1 : 3
Moles of HCl required = 0.019 x 3
=0.057
concentration = moles/volume
volume = 0.057 / 0.1
= 0.57 dm³
= 570 ml
3 0
3 years ago
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