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3 years ago

What are newtons laws of motion?

Physics

1 answer:

yawa3891 [41]3 years ago

3 0

Answer:

In classical mechanics, Newton's laws of motion are three laws that describe the relationship between the motion of an object and the forces acting on it. The first law states that an object either remains at rest or continues to move at a constant velocity, unless it is acted upon by an external force.

Explanation:

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What do you call rocxs that form under intense heat and pressure

kirill [66]

Metamorphic

Metamorphic rocks are formed under the surface of the earth from the metamorphosis (change) that occurs due to intense heat and pressure (squeezing).

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3 years ago

Your mother asks you to carry a load of wood to the fireplace and lower it to the hearth. In doing this you have used your arms

Evgesh-ka [11]

Answer: The correct answer is the weight of the wood.

Explanation:

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8 0

3 years ago

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You measure the pressure of the four tires of your car each to be 35.0 pounds per square inch (psi). You then roll your car forw

Oksi-84 [34.3K]

Answer:

Weight of car = 36034.88 lb.ft/s²

Explanation:

We are told the pressure of the four tires of your car is; P = 35.0 psi

Also, the surface area of contact is; A = 32 in²

Thus;

Weight of tires = Pressure × Area

W_tires = 35 × 32

Weight_tires = 1120lb.

To get the weight of the car, we will multiply the tire weight by acceleration due to gravity.

It's value in ft/s² is g = 32.174 ft/s²

Thus;

Weight of car = 1120 × 32.174

Weight of car = 36034.88 lb.ft/s²

5 0

3 years ago

A low orbit satellite at 100 km altitude had a camera that resolved a car location to within 0.3 meter. Find the minimum diamete

NeX [460]

Answer:

Minimum diameter of the camera lens is 22.4 cm

The focal length of the camera's lens is 300cm

Explanation:

y = Resolve distance = 0.3 m

h = Height of satellite = 100 km

λ = Wavelength = 550 nm

Angular resolution

$tan\theta\approx \theta =\frac{y}{h}\\\Rightarrow \theta=\frac{0.3}{100\times 10^3}=3\times 10^{-6}$

From Rayleigh criteria

$sin\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{sin\theta}\\\Rightarrow D=1.22\frac{550\times 10^{-9}}{sin3\times 10^{-6}}=0.2236\ m=22.4\ cm$

Minimum diameter of the camera lens is 22.4 cm

Relation between resolvable feature, focal length and angular resolution

$d=f\Delta \theta\\\Rightarrow f=\frac{d}{\Delta \theta}\\\Rightarrow f=\frac{9\times 10^{-6}}{3\times 10^{-6}}=3\ m=300\ cm$

The focal length of the camera's lens is 300cm

3 0

3 years ago

A 200 kg roller coaster is located at the top of a hill where the height is 30 m. What is the velocity when it reches the bottom

maw [93]

Assuming it starts at rest, the roller coaster only has potential energy at the top of the hill, which is

$E_P=(200\,\mathrm{kg})(30\,\mathrm m)g$

When it reaches the bottom, its potential energy will have converted to kinetic energy,

$E_K=\dfrac12(200\,\mathrm{kg})v^2$

where $v$ is its velocity at that point. By the law of conservation of energy, assuming no loss of energy due to other sources (e.g. sound, heat), we have

$E_P=E_K\iff(6000\,\mathrm{kg}\cdot\mathrm m)g=(100\,\mathrm kg})v^2$

$\implies v=\sqrt{60g}\,\dfrac{\rm m}{\rm s}\approx24.2\,\dfrac{\rm m}{\rm s}$

8 0

3 years ago

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