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saveliy_v [14]
3 years ago
8

Why does the fed rarely change the reserve requirement

Physics
2 answers:
Brut [27]3 years ago
8 0

The answer is:

It can be disruptive to the whole banking system.

Thepotemich [5.8K]3 years ago
5 0

Answer:

It can be disruptive to the whole banking system.

Explanation:

Gradpoint answer np....

Gradpoint is hard, but I just finished 10 units already in the past 3 days so yesssss.

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What would happen to the two balls if one of them were kept positively charged and the charge on the other ball were slowly incr
mariarad [96]

Answer:

the balls would move closer to each other

Explanation:

8 0
3 years ago
I have my answers I want to know am I correct. Thank you
AfilCa [17]

Answer:

different poles

Explanation:

different poles attract to each other while same poles repel each other . just remember the old saying opposites attract and likes repel .

4 0
4 years ago
Read 2 more answers
A motorboat and a pwc are meeting head-on. which one is the stand-on vessel?
trapecia [35]
This is a boating question not really a physics questions, but googling the rules says the motorboat is the stand on vessel. The pwc is, by class, lighter than the motorboat so it has more maneuverability and thus should be the one to change course. The motorboat is the stand on vessel, so it keeps it's course and speed unchanged.
5 0
4 years ago
Select the correct answer from the drop-down menu. anne applies a force on a toy car and makes it move forward. what can be said
nalin [4]

Answer:

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6 0
2 years ago
a force of 5 N extends a spring of natural length 0.5m by 0.01, what will be the length of the spring when the applied force is
vova2212 [387]

Answer:

L_new =L+x^2  = L_new = 0.54_m.

Explanation:

Given data:

Force in the first case,  

F_1 = 5N

Force in the second case,  

F_2 = 20 N

Natural length of spring,  

L= 0.5

Extension in the first case,  

x_1 = 0.01m

Let the force constant of the spring be k.

Thus,

F_1=kx_1

5 = k × 0.01  

⇒ k = 500 N/m.

The extension in the spring in the second case can be given as,

F_2=kx_2

20 = 500x_2

⇒ x_2 = 0.04 m.

Thus, the effective length of the spring would be,

L_new =L+x^2

L_new = 0.5+0.04

L_new = 0.54_m.

5 0
3 years ago
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