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nordsb [41]
2 years ago
14

When does the net flux of dissolved molecules stop

Physics
1 answer:
Mnenie [13.5K]2 years ago
5 0

The net fluid flux usually stops when the amount or concentration of osmotic active molecules is equal (the same) in the two areas (compartment)

For better understanding let's explain what statement above means

  • Net fluid flux simply ends when the rate(concentration) of the substance is at the same proportion in both areas. It does not implies that movement is not taken place by molecules of that substance but that there is no final movement in one direction simply pit it that the molecules of substance are equally going in both directions (area).

From the above we can therefore say that the answer The net fluid flux usually stops when the amount or concentration of osmotic active molecules is equal (the same) in the two areas (compartments) correct

Learn more about osmotic pressure from:

brainly.com/question/15180636

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The radioactive isotope U-238 has protons and neutrons.
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Answer:

92 protons, 146 neutrons

Explanation:

Uranium will always have the same amount of protons, because that is what defines the element. Uranium has 92 protons, meaning that the rest of the mass of the atom comes from neutrons. 238-92=146 neutrons. Hope this helps!

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A motion sensor emits sound, and detects an echo 0.0115 s after. A short time later, it again emits a sound, and hears an echo a
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Answer:

1.17 m

Explanation:

From the question,

s₁ = vt₁/2................ Equation 1

Where s₁ = distance of the reflecting object for the first echo, v = speed of the sound in air, t₁ = time to dectect the first echo.

Given: v = 343 m/s, t = 0.0115 s

Substitute into equation 1

s₁ = (343×0.0115)/2

s₁ = 1.97 m.

Similarly,

s₂ = vt₂/2.................. Equation 2

Where s₂ = distance of the reflecting object for the second echo, t₂ = Time taken to detect the second echo

Given: v = 343 m/s, t₂ = 0.0183 s

Substitute into equation 2

s₂ = (343×0.0183)/2

s₂ = 3.14 m

The distance moved by the reflecting object from s₁ to s₂ = s₂-s₁

s₂-s₁ =  (3.14-1.97) m = 1.17 m

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