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Anastaziya [24]
4 years ago
13

Which equation is not an identity?

Mathematics
1 answer:
Molodets [167]4 years ago
3 0
D because cos
{ \cos(t) }^{2}  +  \sin(t)  {}^{2}  = 1

p/s : follow me and I will help you more about maths
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Solve the system by graphing. It is REQUIRED to check your solution. Show work for this problem on your work page.
Hunter-Best [27]

Answer:

y=x-1

y=-2x-4

although I cant summon a graph for this one, I can give cords

for first graph (-2,-3),(-1,-2),(0,-1), (1,0),(2,1)

For second graph the slope is down 2 over 1, and begins at (0,-4).

(-2,0)(-1,-2),(0,-4),(1,-6),(2,-8)

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Answer:

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Caleb: 4, 4, 4, 4, 4, 4, 4

Step-by-step explanation:

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3 years ago
In the figure, triangle CAE is an enlargement of triangle CBD with scale factor of 4/3. The area of the smaller triangle is 9cm2
balandron [24]

Answer:

16 cm^2

Step-by-step explanation:

Given

\triangle CAE -- Bigger Triangle

\triangle CBD -- Smaller Triangle

k = \frac{4}{3} --- Scale factor

Area of CBD = 9

Required

Determine the area of CAE

The area of triangle CBD is:

A_1 = \frac{1}{2}bh

\frac{1}{2}bh = 9

The area of CAE is:

A_2 = \frac{1}{2}BH

Where:

B = \frac{4}{3}b and

H = \frac{4}{3}h

The above values is the dimension of the larger triangle (after dilation).

So, we have:

A_2 = \frac{1}{2}*\frac{4}{3}b * \frac{4}{3} * h

A_2 = \frac{1}{2}*\frac{4}{3} * \frac{4}{3} *b* h

A_2 = \frac{1}{2}*\frac{16}{9}  *b* h

Re-order

A_2 = \frac{16}{9}*\frac{1}{2}* b* h

A_2 = \frac{16}{9}*\frac{1}{2}bh

Recall that:

\frac{1}{2}bh = 9

A_2 = \frac{16}{9}*9

A_2 = 16

Hence, the area is 16 cm^2

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3 years ago
What mixed number represents the length of the phone screen
Anni [7]
That depends on the length of the phone

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