let x=k
D=dog
T=Taxes
I=increase P=population
solve k
d=23,000
t=2000
d=2.3e^
divide both sides by 2
after year is,2000+k2-2.3
=1.999.7
k2- 23,000=
k-x
or
k2-2
If I could give you an answer, I would. But I'm terrible at Math so, sorry
Answer:
c
Step-by-step explanation:
Answer:
Assuming 1/20 is a 5% late fee:
$21.211
Step-by-step explanation:
67.82 x 1/20 = 3.391
67.82 + 3.391 = 71.211
<u>Answer:</u>
Cost of package of paper = 4$
Cost of stapler = 7$
<u>Explanation:</u>
Consider the cost of package of paper = x and that of stapler = y.
Now, we are given that cost of 3 paper packages and 4 staplers = 40$
Hence we get, 3x + 4y = 40 as 1st equation.
we are also given, cost of 5 paper packages and 6 staplers = 62$
Hence, the second equation is 5x + 6y = 62
Now, solving the two equations by method of elimination, we first equate coefficients of any one variable say x by multiplying 1st equation by 5 and second by 3 we get ->
15x + 20y = 200
15x + 18y= 186
Subtracting the two we get y = 7 and substituting this value of y in first equation we get x = 4
which gives the required cost of one paper package = x = 4$
and one stapler = y = 7$
