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3 years ago

WHAT IS HELP PLEASE 6x2 -2x3 +x4 =? DONT ANSWER TO GET QUICK POINTS

Mathematics

2 answers:

Nuetrik [128]3 years ago

8 0

The correct answer is / =10x

blondinia [14]3 years ago

3 0

Answer:

i told you in the comment it equals 7

Step-by-step explanation:

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Stephanie has $4,500 in her saving account.

AfilCa [17]

so whats the question

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3 years ago

Pls help I’ll brainlest solve it like this

sergey [27]

$\frac{3}{5} t = 6$

$t = 6 \div \frac{3}{5}$

$t = 6 \times \frac{5}{3}$

$t = 2 \times 5$

$t = 10$

____________________________

$\frac{1}{4} a = \frac{14}{15}$

$a = \frac{14}{15} \div \frac{1}{4}$

$a = \frac{14}{15} \times 4$

$a = \frac{56}{15}$

7 0

3 years ago

Read 2 more answers

What is 17 1/3 x 8 and how much water will each group get

stealth61 [152]

Answer:

The Answer to 17 1/3 x 8 is 138.67

There is not enough context to answer the second question.

8 0

3 years ago

What number is 28% of 25?

Anvisha [2.4K]

Answer:

Step-by-step explanation:

what number is 28% of 25

Is means equals and of means multiply

N = 28% of 25

Change to decimal form

N = .28* 25

N =7

7 0

3 years ago

Read 2 more answers

In Illinois, 9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been arre

Veseljchak [2.6K]

Answer:

a) 21.58% probability that exactly 3 people are repeat offenders

b) 97.91% probability that at least one person is a repeat offender

c) 3.69

d) 1.83

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders

This means that $p = 0.09$

41 people arrested for DUI in Illinois are selected at random.

This means that $n = 41$

a. What is the probability that exactly 3 people are repeat offenders?

This is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{41,3}.(0.09)^{3}.(0.91)^{38} = 0.2158$

21.58% probability that exactly 3 people are repeat offenders

b. What is the probability that at least one person is a repeat offender?

Either none are repeat offenders, or at least one is. The sum of the probabilities of these outcomes is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ .

Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = 0) = C_{41,0}.(0.09)^{0}.(0.91)^{41} = 0.0209$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0209 = 0.9791$

97.91% probability that at least one person is a repeat offender

c. What is the mean number of repeat offenders?

$E(X) = np = 41*0.09 = 3.69$

d. What is the standard deviation of the number of repeat offenders?

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{41*0.09*0.91} = 1.83$

4 0

3 years ago