A truck can carry a maximum of 1350 ponds of weight .how many 250- pound of dirt can the truck hold

Can someone explain to me how to find the area of this please?

natita [175]

Area is 118in^2 Hope this helps

8 0

3 years ago

For the following exercises, determine whether the functions are even, odd, or neither.

stealth61 [152]

Answer:

The solutions of the equation |2 x-3|=17

are x=10

and x=-7

Step-by-step explanation:

Given equations is |2 x-3|=17.

It is required to find out the values of x satisfying the given equation.

To find it out, use the fact that the solution of this type of equation is 2x-3=17.

Or 2x-3=-17 and simplify the equations using simple mathematical operations.

Step 1 of 2

Solve the equation 2x-3=17,

Add 3 on both sides of the equation 2x-3=17,

2x-3+3=17+3

2x=20

Divide by 2 on both sides of the equation 2x=20,

$\begin{aligned}&\frac{2 x}{2}=\frac{20}{2} \\&x=10\end{aligned}$

Step 2 of 2

Solve the equation 2x-3=-17,

Add 3 on both sides of the equation 2x-3=-17,

$2 x-3+3=-17+3$\\ $2 x=-14$

Divide by 2 on both sides of the equation 2x=-14,

$\begin{aligned}&\frac{2 x}{2}=\frac{-14}{2} \\&x=-7\end{aligned}$

6 0

2 years ago

Ship Co. produces storage crates that require 1.2 meters of material at $.85 per meter and 01 direct labor hours at $15.00 per h

Vesna [10]

Answer:

$3.42

Step-by-step explanation:

Meters of material required = 1.2 meters

Cost per meter of material = $0.85

Direct labor hours = 0.1

Cost of direct labor per hour = $15

Overhead rate = $9 per direct labor hour

Standard cost per unit of product :

(Direct material cost per unit + direct labor cost per unit + overhead cost per unit)

Direct material cost per unit :

Material needed × cost per meter = (1.2 × $0.85) = $1.02

Direct labor cost per unit :

Direct labor hour × cost per hour = ( 0.1 × $15) = $1.5

Overhead cost:

0.1 * $9 = $0.9

Standard cost :

($1.02 + $1.5 + $0.9) = $3.42

5 0

3 years ago

Can yall help meee please

alexira [117]

Answer:

$jupiters \: mass \: is \: approximatelty \: \\ \boxed{{6 \times 10}^{3} \: kg} \: times, \: \\ more \: than \: mercurys \: mass$

Step-by-step explanation:

$............................................................... \\ in \: other \: to \: get \: right \: ans \to \\ you \: divide \: mass \: of \: jupiter \: by \: the \: mass \\ \: of \: mercury : \: so \to \\ ............................................................... \\ jupiters \: mass = 1.898 { \times 10}^{27} \: kg \\ mercurys \: mass =3.3 \times {10}^{23} \: kg \\ their \: mass \: ratio \: is : \\ = \frac{1.898 { \times 10}^{27}}{3.3 \times {10}^{23}} = 0.5751515152 \times {10}^{4} = \\ \boxed{5,751.515152} \\ hence \: jupiters \: mass \: is \: approximatelty \: \\ {6 \times 10}^{3} \: times \: more \: than \: mercurys \: mass$

5 0

2 years ago

Read 2 more answers

The city park department is planning to enclose a play area with fencing. One side of the area will be against an existing build

Oksanka [162]

Answer:

The maximum rectangular area will have the length 400 meters and width 200 meters with one side of the length against an existing building.

Step-by-step explanation:

From the given information;

The perimeter of a rectangle = 2 (L+B)

here;

L = the length of the side of the fence

B = the width of the fence

So; The perimeter of a rectangle = 2L+2B

we are also being told that;

One side of the area will be against an existing building

i.e

The perimeter of a rectangle is now = L + 2B = 800 meters

L = 800 - 2B

Similarly; Area of a rectangle = L × B

Area of a rectangle = ( 800 - 2B) × B

Area of a rectangle = 800B - 2B²

assuming A(B) to represent the Area;

Then the maximum area A'(B) = 0 ;

Thus,

A'(B) = 800 - 4B = 0

-4B = - 800

4B = 800

B = 200

Therefore; the maximum area have a width = 200 meters and a length 800 - 2(200) = 800 - 400 = 400 meters

3 0

3 years ago