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2 years ago

8

A middle school has 600 students and 34% of them are in eighth grade 1/4 of eighth graders walk to school how many eighth-grade

students walk to school

1 answer:

Nonamiya [84]2 years ago

5 0

You have to find how many kids are in eighth grade so you would multiply 34x6 and get 204 then you decide that by 1/4 and you get 51

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I need help if anyone can help me with a few problems please help me

jok3333 [9.3K]

I think it’s the number 3 I’m not sure I’m learning this stuff rn I’m getting the hang of it just it’s hard and not hard at the same time

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3 years ago

risha wants to buy a computer for $775. She already has $275 saved and earns $100 a week babysitting. a. Use w to represent week

Alisiya [41]

Answer

Inequality=100x+275≥775 Answer=5 or more

Step-by-step explanation:

5 0

2 years ago

Arm Span(x) Height(y)

natita [175]

Answer:

Here's what I get.

Step-by-step explanation:

1. Representation of data

I used Excel to create a scatterplot of the data, draw the line of best fit, and print the regression equation.

2. Line of best fit

(a) Variables

I chose arm span as the dependent variable (y-axis) and height as the independent variable (x-axis).

It seems to me that arm span depends on your height rather than the other way around.

(b) Regression equation

The calculation is easy but tedious, so I asked Excel to do it.

For the equation y = ax + b, the formulas are

$a = \dfrac{\sum y \sum x^{2} - \sum x \sumxy}{n\sum x^{2}- \left (\sum x\right )^{2}}\\\\b = \dfrac{n\sumx y - \sum x \sumxy}{n\sum x^{2}- \left (\sum x\right )^{2}}$

This gave the regression equation:

y = 1.0595x - 4.1524

(c) Interpretation

The line shows how arm span depends on height.

The slope of the line says that arm span increases about 6 % faster than height.

The y-intercept is -4. If your height is zero, your arm length is -4 in (both are impossible).

(d) Residuals

$\begin{array}{cccr}&\textbf{Arm Span} & \textbf{Arm Span}&\\\textbf{Height/in} &\textbf{Actual} & \textbf{Predicted}&\textbf{Residual}\\25 & 19 & 22.3 & -3.3\\40 & 41 & 38.2 & 2.8\\55 & 51 & 54.1 & -3.1\\65 & 67 & 62.6 & 4.4\\ \end{array}$

The residuals appear to be evenly distributed above and below the predicted values.

A graph of all the residuals confirms this observation.

The equation usually predicts arm span to within 4 in.

(e) Predictions

(i) Height of person with 66 in arm span

$\begin{array}{rcl}y& = & 1.0595x - 4.1524\\66 & = & 1.0595x - 4.1524\\70.1524 & = & 1.0595x\\x & = & \dfrac{70.1524}{1.0595}\\\\& = & \textbf{66 in}\\\end{array}\\\text{A person with an arm span of 66 in should have a height of about $\large \boxed{\textbf{66 in}}$}$

(ii) Arm span of 74 in tall person

$\begin{array}{rcl}y& = & 1.0595x - 4.1524\\& = & 1.0595\times74 - 4.1524\\& = & 78.4030 - 4.1524\\& = & \textbf{74 in}\\\end{array}\\\text{ A person who is 74 in tall should have an arm span of $\large \boxed{\textbf{74 in}}$}$

6 0

3 years ago

What is the missing part

mihalych1998 [28]

Answer: the missing part is 45

suppose: the missing part is x

we use Thales theorem:

$\frac{x}{18}=\frac{20}{8}\\\\=> x = \frac{20.18}{8}=45$

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Amswer this question

disa [49]

they need to be 8 each sides

well if 4 squares are = to 3 and its a cube then all the sides must be even

so if 3x2=6 and you need the square to have 6 as its sides then you need to get 4x2 which = 8

7 0

3 years ago