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Arisa [49]
2 years ago
12

, Natasha worked 7 hours at a diner for $10 per hour last week. She also makes $8 per hour when she babysits. She wants $206 for

a prom dress. Create an inequality to show how many hours she must babysit.
Mathematics
1 answer:
AfilCa [17]2 years ago
3 0

Answer: x ≥ 17

Step-by-step explanation:

We know that she worked 7 hours at a dinner, for $10 per hour last week.

Then in the last week, she did make:

7*$10 = $70

Now she babysits, she wins $8 per hour, then if she works x hours, she will win:

w(x) = $8*x

if we add the $70 that she already had, we have:

$70 + $8*x

And we know that she wants to have, at least, $206, then we can write the inequality.

$70 + $8*x ≥ $206.

Now let's solve this for x.

first, we can subtract $70 in both sides:

($70 + $8*x) - $70 ≥ $206 - $70

$8*x ≥ $136

now we can divide by $8 in both sides:

($8*x)/$8 ≥ $136/$8

x ≥ 17

This means that she must babysit for at least 17 hours if she wants to buy the dress.

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What is the 38th term of 459,450,441,..
galina1969 [7]

Answer:

The 38th term of 459,450,441,.. will be:

a_{13}=351

Step-by-step explanation:

Given the sequence

459,450,441,..

An arithmetic sequence has a constant difference 'd' and is defined by

a_n=a_1+\left(n-1\right)d

computing the differences of all the adjacent terms

450-459=-9,\:\quad \:441-450=-9

so

d=-9

The first element of the sequence is

a_1=459

so the nth term will be

a_n=-9\left(n-1\right)+459

a_n=-9n+468

Putting n=38 to find the 38th term

a_n=-9n+468

a_{13}=-9\left(13\right)+468

a_{13}=-117+468

a_{13}=351

Therefore, the 38th term of 459,450,441,.. will be:

a_{13}=351

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3 years ago
Help plz
sergiy2304 [10]
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84 is what percent of 212? round three decimal points before changing to a percent
Olegator [25]

The answer is 39.62%.

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Winston wants to put some very thick books on his bookshelf. Each book is 3 inches
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1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the
Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

f(x)=e^{3x}+\cos(5x),

g(x)=e^{3x}-\cos(5x),

h(x)=\cos(5x).

Then, letting α = 1, β= -1 and ω = -2, we see that:

\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

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