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3 years ago

Examples: Find the value of x.

Mathematics

1 answer:

Zolol [24]3 years ago

6 0

Answer:

Step-by-step explanation:

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Factorise x^2-12x+32

Volgvan

workings...

-8x-4=32

-8-4=12

answer: (x-8)(x-4)

7 0

3 years ago

Karin wants to use the distributive property to mentally find the value of 19 x 42+ 19x 58. Which expression can she use?

ipn [44]

19 x (42 + 58) or 19*(42 + 58) is the expression she can use. You factor out the common term 19. The distributive rule says that we can multiply the outer 19 with each term inside to get the original expression again.

8 0

4 years ago

Two supplementary angles are congruent. Which equation gives the measure in degrees, d, of each angle?

Nimfa-mama [501]

Solution:

The given statement is :Two supplementary angles are congruent.

Two angles are said to be supplementary if sum of these two angles is 180°.

Let one Angle be A, then another angle will be 180 - A.

As given:

A≅180-A

A=180 -A

A +A= 180

2 A = 180

Dividing both sides by 2, we get

A= 90°

The Measure of each angle will be of 90°.

i.e , d = 90°

5 0

3 years ago

Read 2 more answers

Compute (3/4)*(8/9)*(15/16)*(24/25)*(35/36)*(48/49)*(63/64)*(80/81)*(99/100) Express your answer in the simplest way possible. (

Alenkinab [10]

Answer:

$(\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}) = \frac{11}{20}$

Step-by-step explanation:

Given

$(\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100})$

Required

Simplify

For clarity, group the expression in threes

$((\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

Evaluate the first group [Divide 8 by 4]

$((\frac{3}{1})*(\frac{2}{9})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

[Divide 9 by 3]

$((\frac{1}{1})*(\frac{2}{3})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

$((\frac{2}{3})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

[Divide 15 by 3]

$((\frac{2}{1})*(\frac{5}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

[Divide 16 by 2]

$((\frac{1}{1})*(\frac{5}{8}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

$(\frac{5}{8})*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

Evaluate the second group [Divide 35 and 25 by 5]

$(\frac{5}{8})*((\frac{24}{5})*(\frac{7}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

[Divide 49 by 7]

$(\frac{5}{8})*((\frac{24}{5})*(\frac{1}{3})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

[Divide 24 by 3]

$(\frac{5}{8})*((\frac{8}{5})*(\frac{1}{1})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

$(\frac{5}{8})*((\frac{8}{5})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

Merge the first and second group

$((\frac{5}{8})*(\frac{8}{5})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

$(1*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

$(\frac{4}{7})*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))$

Evaluate the last group [Divide 99 by 9]

$(\frac{4}{7})*((\frac{63}{64})*(\frac{80}{9})*(\frac{11}{100}))$

[Divide 63 by 9]

$(\frac{4}{7})*((\frac{7}{64})*(\frac{80}{1})*(\frac{11}{100}))$

[Divide 64 and 80 by 8]

$(\frac{4}{7})*((\frac{7}{8})*(\frac{10}{1})*(\frac{11}{100}))$

[Divide 10 and 4 by 2]

$(\frac{4}{7})*((\frac{7}{4})*(\frac{5}{1})*(\frac{11}{100}))$

[Divide 100 by 5]

$(\frac{4}{7})*((\frac{7}{4})*(\frac{1}{1})*(\frac{11}{20}))$

$(\frac{4}{7})*((\frac{7}{4})*(\frac{11}{20}))$

$(\frac{4}{7})*(\frac{7}{4})*(\frac{11}{20})$

$1*(\frac{11}{20})$

$\frac{11}{20}$

Hence;

$(\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}) = \frac{11}{20}$

4 0

3 years ago

If the circumference of a circle measures 3/2pi cm, what is the area of the circle in terms of pi

nasty-shy [4]

The area of circle in terms of pi is $\frac{9}{16}\pi \ cm^2.$