Answer:
X-intercept= (1/2,0) Y-intercept= (0,1)
Step-by-step explanation:
You're welcome :)
Whisper-20dB
Quiet Residence-30dB
Soft stereo in Residence-40dB
Average Speech-60dB
Cafeteria-80dB
Pneumatic Jackhammer-90dB
Loud crowd noise-100dB
Accelerating Bike-100dB
Rock concert-120dB
Jet Engine (75 ft away)-140dB
(1)Mode=100dB (since 100 is occurring the maximum no. of times, i.e. it has the highest frequency of 2)
(2)Mean=sum of observations/Total number of observations
=(20+30+40+60+80+90+100+100+120+140)/10
=770/10=10dB
(3)Median= 1/2[{n/2}th observation + {(n/2)+1}th observation], where, n=total no. of observations
So, 1/2[{10/2}th observation + {(10/2)+1}th observation]
=1/2[5th observation+6th observation]
=1/2[80+90] [Because:5th observation=80dB and 6th=90dB]
=1/2(170)
=85
Therefore, median=85dB
Answer:
scooter A= 75 scooter b= 90
Answer:
The correct option is (c)
Justin is working with continuous quantitative type of data.
Step-by-step explanation:
We are given that Justin is collecting data on reaction time.
The reaction time is obtained through measurements and it can take any value within a range therefore, it falls in the category of continuous data.
Moreover, since reaction time can be measured thus have numerical value therefore, it is a quantitative type of data.
Therefore, we can conclude that Justin is working with continuous quantitative type of data.
Other examples of continuous quantitative type of data are
measuring height
measuring temperature
