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Pepsi [2]
3 years ago
5

The function is used to convert temperature from Celsius (C) to Fahrenheit (F). The function C(K) = K − 273.15 is used to conver

t temperature from Kelvin (K) to Celsius. Which is the correct function for converting temperature from Kelvin to Fahrenheit?
Mathematics
1 answer:
ANTONII [103]3 years ago
8 0

Answer:

F(k)= \frac{9}{5}(k - 273.15) + 32

 

Step-by-step explanation:

Given

F(c)= \frac{9}{5}c + 32

C(k) = k - 273.15

Required

Function from K to F

This implies that, we calculate F(k)

Given that:

F(c)= \frac{9}{5}c + 32

Substitute c(k) for c

F(c(k))= \frac{9}{5}c(k) + 32

Substitute: C(k) = k - 273.15

F(c(k))= \frac{9}{5}(k - 273.15) + 32

Hence:

F(k)= \frac{9}{5}(k - 273.15) + 32

You might be interested in
What is the slope of a line that is perpendicular to the line y= 1/3 x - 2
drek231 [11]

Answer:

slope = - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{1}{3} x - 2 ← is in slope- intercept form

with slope m = \frac{1}{3}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{1}{3} } = - 3

4 0
3 years ago
S
zzz [600]

Answer:

x = 4

Step-by-step explanation:

A trapezium is a quadrilateral (has four sides and four angles) with one pair of parallel sides. A trapezium is said to be isosceles if the bases are parallel, the two other sides known as the legs are equal and diagonals of the trapezium are equal to each other.

In trapezoid ABCD, BC and AD are the diagonals.

Hence BC = AD (property of isosceles trapezoid)

9x + 1 = 12x - 11

Simplifying:

12x - 9x = 1 + 11

3x = 12

Dividing both sides by 2:

x = 4

8 0
2 years ago
The length of a rectangle is 5 meters less than twice the width. If the area of the rectangle is 273 meters, find the dimensions
AleksandrR [38]

The length of the rectangle = 16 meters

The width of the rectangle = 10.5 meters

<u>Step-by-step explanation</u>:

Given that,

The Area of the rectangle is 273.

<u><em>Step 1</em></u><em> :</em>

Let, the width of the rectangle be 'x'

The length of the rectangle is 2x - 5

<u><em>Step 2</em></u><em> :</em>

Area of the rectangle = length \times width

                             273 = (2x - 5) x

                             273 = 2x^2 - 5x

<u><em>Step 3</em></u><em> :</em>

The equation formed is 2x^2 - 5x -273 = 0

a= coefficient of x^2 = 2

b= coefficient of x = -5

c = constant = -273

Find the roots of the equation, to find the width.

<u><em>Step 4</em></u><em> :</em>

Find the roots using factorizing method,

ac = 2\times-273 = -546 and b= -5

Factorizing -546 as -26\times21

The product of -26\times21 = -546

The sum of -26 + 21 = -5

<u><em>Step 5</em></u><em> :</em>

The roots of the equation 2x^2 - 5x -273 = 0 are x= -26/2 and x= 21/2

The values of x are x= -13 and x= 10.5

Since the width cannot be a negative value, neglect x= -13

<u><em>Step 6</em></u><em> :</em>

Therefore,

The width of the rectangle = 10.5 meters

The length of the rectangle = 2x-5

                                                = 2(10.5) - 5

                                                = 21 - 5

                                    length = 16 meters

5 0
3 years ago
Which of the following pairs of points are both solutions to the equation 2x-5y=6 ? and and and and
zhannawk [14.2K]

Answer:

Any points on the line y=2/5 x - 6/5. See picture below.

Step-by-step explanation:

Convert the equation to slope intercept form and graph it.

2x - 5y = 6

-5y = 6 - 2x

y = -2/-5 x + 6/-5

y=2/5 x - 6/5.

Locate each of the points listed on the graph. If they are a part of the line, then they are solutions.

3 0
3 years ago
What is the following quotient? StartFraction RootIndex 3 StartRoot 60 EndRoot Over RootIndex 3 StartRoot 20 EndRoot EndFraction
FrozenT [24]

Answer:

\sqrt[3]{3}

Step-by-step explanation:

We are required to simplify the quotient: \dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}

Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:

\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}

=\sqrt[3]{3}

The simplified form of the given quotient is \sqrt[3]{3}.

6 0
3 years ago
Read 2 more answers
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