The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
<h3>Ratio of the areas of similar figures </h3>
From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>
<u />
The two figures are similar
From one of the theorems for similar polygons, we have that
If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²
Let the base length of the first figure be ,m = 14 mm
and the base length of the second figure be, n = 7 mm
∴ The ratio of their areas will be



= 4:1
Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446
Okay? Whats the point? If You're trying to find out how long it would take then you would have to make $500 so 45 more hours until you can get it.
To answer the problem just add the frequencies that
correspond to email counts that are 19 or fewer. So you're adding the counts
that correspond to 0-9 and 10-19. So the frequency of 0-9 is 4 and the
frequency of 10 -19 is 7. So 4 + 7 = 11
X^2 - 3x + 2 =
(x - 1)(x - 2) <==
Use the kinematics equation:
v1^2-v0^2=2as
since v1=0 (at height of 81 ft), and a=g=-32.2, substitute values:
0-v0^2=2*(-32.2)(81 ft)
Solve for v0
v0=sqrt(2*32.2*81)=72.2 m/s