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mojhsa [17]
2 years ago
6

Please help me! No one ever does! will give 30 points and brainliest!

Computers and Technology
1 answer:
Alekssandra [29.7K]2 years ago
6 0

Answer:

The term digital citizenship, also known as e-citizenship or cyber-citizenship, refers to the use of Information and Communication Technologies (ICT), and the principles that guide them, for the understanding of the political, cultural and social issues of a nation.

More Content by Concept

In other words, it is about citizen participation through digital or electronic environments and interfaces, through the Internet and Social Networks.

Digital citizenship is part of the electronic government system or digital democracy, which precisely consists of the administration of State resources through new ICTs and all their potential, to make life easier for citizens.

In this way, a digital citizen has the right to access information online in a safe, transparent and private way, in addition to the social and political participation that 2.0 media allows.

Explanation:

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Write a program roman which converts numbers from decimal notation into Roman numerals. roman takes a single argument, a string
MaRussiya [10]

Answer:

// Program is written in C++ programming language

/ Comments are used for explanatory purpose

// Program starts here

#include<bits/stdc++.h>

using namespace std;

//Declare a function named value to represent the symbols of Roman Numerals

int value(char xy)

{

if (xy == 'I') { return 1; }

if (xy == 'V') { return 5; }

if (xy == 'X') { return 10; }

if (xy == 'L') { return 50; }

if (xy == 'C') { return 100; }

if (xy == 'D') { return 500; }

if (xy == 'M') { return 1000; }

return -1;

}

// Convert to numbers , taking Variable named input as input

int Converted(string &input)

{

// Declare a variable to store the calculated output

int calc;

// Set to 0

calc = 0;

// Iterate through input from 0 to the last character

for (int i=0; i<input.length(); i++)

{

int check1 = value(input[i]);

if (i+1 < input.length())

{

int check12= value(input[i+1]);

// Comparing both values

if (check1>= check2)

{

calc+ =check1;

}

else

{

calc+ =check2 - check1;

i++;

}

}

else

{

calc+ =check1;

}

}

return calc;

}

// Main method starts here

int main()

{

// String input declaration

string inp;

cout<"Enter any valid Roman numeral";

cout << "Result is "

<< Converted(inp);

return 0;

}

3 0
3 years ago
Carlos is using the software development life cycle to create a new app. He has finished coding and is ready to see the output i
Nitella [24]

Answer:

Testing

Explanation:

From the question, we understand that Carlos just finished the coding of the app.

In software development life cycle, the coding phase is where Carlos is expected to make use of his choice of programming language to design the app;

This stage is an integral part of the implementation process and according to the question, the coding has been completed;

The next phase or stage after the implementation phase is testing.

Hence, Carlos is getting ready to test the app.

4 0
2 years ago
Read 2 more answers
Wi-Fi is designed for medium-range transfers, up to ____ feet outdoors. Answer 100 300 500 900
Papessa [141]
Wi-Fi is designed for medium range transfers up to 900 feet out doors. ANSWER: 900 feet
6 0
3 years ago
Select the correct answer.
Serga [27]

B: feasibility study

They are analyzing whether the project or application makes sense or is feasible, given the available resources, budget and projected monetary gains.

6 0
2 years ago
In the following four questions, we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the pa
pantera1 [17]

Answer:

1)we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Initially suppose there is only one link between source and destination. Also suppose that the entire MP3 file is sent as one packet. The TRANSMISSION DELAY is:

3 Seconds

2)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. The END TO END DELAY(transmission delay plus propagation delay) is

3.05 seconds

3)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. how many bits will the source have transmitted when the first bit arrives at the destination.

500,000 bits

4)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Now suppose there are two links between source and destination, with one router connecting the two links. Each link is 5,000 km long. Again suppose the MP3 file is sent as one packet. Suppose there is no congestion, so that the packet is transmitted onto the second link as soon as the router receives the entire packet. The end-to-end delay is

6.1 seconds

5)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Now suppose that the MP3 file is broken into 3 packets, each of 10 Mbits. Ignore headers that may be added to these packets. Also ignore router processing delays. Assuming store and forward packet switching at the router, the total delay is

4.05 seconds

6)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Now suppose there is only one link between source and destination, and there are 10 TDM channels in the link. The MP3 file is sent over one of the channels. The end-to-end delay is

30.05 seconds

7)

we are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108 meters/sec, and the distance between source and destination is 10,000 km. Now suppose there is only one link between source and destination, and there are 10 FDM channels in the link. The MP3 file is sent over one of the channels. The end-to-end delay is

30.05 seconds

6 0
3 years ago
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