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Usimov [2.4K]
2 years ago
5

1. The zeros of a quadratic relation are 3 and The second differences are positive

Mathematics
1 answer:
nata0808 [166]2 years ago
8 0

Answer:

The optimal, vertex, value will be a minimum

Step-by-step explanation:

The given zeros of the quadratic relation are 3 and 3

The sign of the second differences of the quadratic relation = Positive

Whereby the two zeros are the same as x = 3, we have that the point 3 is the optimal value or vertex (the repeated point in the graph of the quadratic relation) of the quadratic relation

Whereby, the table of values for the quadratic relation from which the second difference is found starts from x = 3, we have;

To the right of the coordinate points of the zeros of the quadratic relation, the positive second difference in y-values gives as x increases, y increases which gives a positive slope

By the nature of the quadratic graph, the slope of the line to the left of the coordinate point of the zeros of the quadratic relation will be of opposite sign (or negative). The quadratic relation is cup shaped and the zeros, therefore, the optimal value will be a minimum of the quadratic relation

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son4ous [18]
step 1
<span>compute the average: add the values and divide by 6
Average =(44+ 46+40+34+29+41)/6=39

step 2
</span><span>Compute the deviations from the average
dev: (44-39)=5,
</span>dev: (46-39)=7
dev: (40-39)=1
dev: (34-39)=-5
dev: (29-39)=-10
dev: (41-39)=2

step 3
<span>Square the deviations and add
sum (dev^2): 5^2+7^2+1</span>^2+-5^2+-10^2+2^2
sum (dev^2): 25+49+1+25+100+4-----> 204

step 4
<span>Divide step #3 by the sample size=6
(typically you divide by sample size-1 to get the sample standard deviation,
 but you are assuming the 6 values are the population,
so
no need to subtract 1, from the sample size.
This result is the variance
Variance =204/6=34

step 5
</span><span>Standard deviation = sqrt(variance)
standard deviation= </span>√<span>(34)------> 5.83

the answer is
5.83</span>


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2 years ago
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Answer:

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Step-by-step explanation:

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