Answer:
293.38 pounds
Step-by-step explanation:
We are given that
Distance between poles=35 feet

Weight of cable=10.4 per linear foot
We have to find the weight of the cable.
Differentiate w.r.t




Let 


![s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B2%7D%7B0.0225%7D%5Ctimes%5Cfrac%7B2%7D%7B3%7D%5Bt%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%5D%5E%7B17.5%7D_%7B0%7D)
![s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D2%5Ctimes%20%5Cfrac%7B2%7D%7B3%5Ctimes0.0225%7D%5B%281%2B0.0255x%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%5D%5E%7B17.5%7D_%7B0%7D)

s=28.21
Weight of cable=
pound
Answer:
d. The slope of the relationship between firstfloorsquarefootage and price is moresteep for homes near the beach than elsewhere in Tampa.
Step-by-step explanation:
In this regression model, we have a positive slope. This positive slope is indicative of an increase. So to interpret this slope, we would say that the slope of the relationship that exists between the two variables (price and firstfloorsquarefootage) is steeper for the homes that are closer to the beach compared to the ones that are elsewhere. Therefore option D is our answer.
(y_final-y_start)/(x_final-x_start) always! :) that easy
(-6-2)/(2-0) = -4
You probably know that if the interval was pretty small, between 0 and 0.0001, it would take you to the concept of slope and derivatives, but average change is just ignoring anything in between x=0, and x=2 (it could go up/down million times, and still the answer would be -4)
hope it helps
Answer:
165.3
Step-by-step explanation: