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ZanzabumX [31]
3 years ago
9

Find a formula for the nth term of the geometric sequence. Assume the n begins with 1. a1=18, a2=9​

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
6 0

Answer:

Option E

Step-by-step explanation:

Explicit formula of a geometric sequence is,

T_n=a_1(r)^{n-1}

Here, a_1= First term

r= common ratio

n= number of terms

If, a_1=18 and a_2=9

Common ratio of the sequence r=\frac{a_2}{a_1}

r=\frac{9}{18}

r=\frac{1}{2}

By substituting these values in the formula,

T_n=18(\frac{1}{2} )^{n-1}

Therefore, Option E is the answer.

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4 0
3 years ago
I need help can anyone help me ​
labwork [276]
In 7 years, the car was 18,000 and after 5 years it is worth 10,500 so if you subtract 18000-10500=7500 and if you do 7500/5=1500 so this means that the car was going down 1500 in value every year.
5 0
2 years ago
Write a function for the situation discribed and find the value after 5 yrs. A $12,500 car depreciates 9% each year. Please help
sweet [91]
\bf \qquad \textit{Amount for Exponential Decay}\\\\
A=P(1 - r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &12500\\
r=rate\to 9\%\to \frac{9}{100}\to &0.09\\
t=\textit{elapsed time}\\
\end{cases}
\\\\\\
A=12500(1-0.09)^t\implies A=12500(0.91)^t
\\\\\\
\textit{after 5 years t = 5}\qquad A=12500(0.91)^5

and surely you know how much that is.
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3 years ago
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