This is true because the water would have gravitational potential energy that is caused by the water being held back by the dam and the water wanting to flow down.
This can be converted into kinetic energy when given the chance to, such as having a turbine on the dam.
Hope this helps! :)
Answer: Volume of 1g of pure gold 
Given;
Density of a pure gold=19.3 
Mass of a pure gold =1g
To find:
Volume of 1g of pure gold
Solution:
According to the formula,
Density= Mass/Volume
Where 
=density of pure gold
m=mass of pure gold
v=volume of pure gold
From the above equation volume can be calculated as
Substitute the values of mass and density value in the above equation
Result:
Thus the volume of 1g of pure gold is
Answer:
43.96secs
Explanation:
M1 = molar mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol
t1 = time for NH3 to diffuse = 30secs
M2 = molar mass of HCl = 1 + 35.5 = 36.5g/mol
t2 = time for HCl to diffuse =?
From Graham's law of diffusion:
t2/t1 = √(M2/M1)
t2/30 = √(36.5/17)
t2/30 = 1.465
Cross multiply
t2 = 30 x 1.465
t2 = 43.96secs
Therefore it will take 43.96secs for the damp blue litmus paper to change colour for HCl.
In a distillation model, it is better to let the cold water enter the bottom of the condenser and exit at the top because this can lead to a better cooling effect.
When water enters from the bottom, they will stay longer in the condenser, thus the vapor in the condenser can be cooled back into liquid faster.
In addition, this method can also save the amount of water used, since they water can stay longer in the condenser.
G(2)=2
For this, you can plug in 2 everywhere you see an n. So the equation will read:
g(2)=g(2-1)+2 -> g(2)=g(1)+2. Since we are given g(1)=0, we can plug in 0 where we see g(1). The equation is now. g(2)=0+2. So, g(2)=2.
