The mass of CO2 that would be produced is 144.03 g
From the equation of the reaction, the mole ratio of C2H4 input to CO2 produced is 1:2.
Recall that: mole = mass/molar mass
mole of 45.9 g C2H4 = 45.9/28.05
= 1.6364 moles
Thus: equivalent moles of CO2 = 1.6364 x 2
= 3.2727 moles
Mass of 3.2727 moles of CO2 = moles x molar mass
= 3.2727 x 44.01
= 144.03 g
More on stoichiometric calculations can be found here: brainly.com/question/8062886?referrer=searchResults
1) Molarity
M = n / V
n: number of moles of solute
V: volume of the solution in liters
n = mass / molar mass = 0.000333 g / 332.32 g / mol = 1*10 ^ - 6 moles
V = 225 ml * 1 liter / 1000 ml = 0.225 liter
M = 10^-6 mol / 0.225 liter = 0.00000444 M
2) ppm
ppm = parts per million
grams of solute: 0.000333 g
grams of solution = volume * density = 225 ml * 0.785 g / ml = 176.625 g
ppm = [0.00033 g / 176.625 g] * 1,000,000 = 1.868 ppm
The answer is A. Nitrogen Oxide
Find the pH using the concentration of hydrogen ions [H+] of 0.001M (molarity) by taking the negative log of the value:
-log[H+]=pH
-log[0.001] = pH
-log[1x10^-3]=pH
3=pH
Answer:
Explanation:
In the solution of AB , they are split to give ions as follows
AB ⇄ A⁺ + B⁻
Product of concentration of A⁺ and B⁻ in saturated solution of AB is constant .
This is called Ksp
Ksp = [A⁺] [ B⁻]
If product of concentration of A⁺ and B⁻ exceeds Ksp , the equilibrium shifts to the left side and excess ions come out of solution in the form of precipitate. So second option is the answer.
