The correct option is FLUORINE AND COPPER.
An ionic compound is usually formed by the combination of a metal and a non metal, the metal usually act as an electron donor while the non metal act as an electron acceptor. Thus, in ionic compounds, there is total transfer of electrons from the metal to the non metal. In the question given here, copper is the metal while the fluorine is the non metal.<span />
a. mass of iron = 69.92 g
b. percent yield = 93%
<h3>Further eplanation
</h3>
Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated
General formula:
Percent yield = (Actual yield / theoretical yield )x 100%
An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients
a.
Reaction
Fe₂O₃+3CO⇒2Fe+3CO₂
MW Fe₂O₃ : 159.69 g/mol
mol Fe₂O₃

mol Fe₂O₃ : mol Fe = 1 : 2
mol Fe :

mass of Fe(Ar=55.845 g/mol) :

b.
actual yield = 65 g
theoretical yield = 69.92 g
percent yield :

Answer:
The covalent bond in Cl₂ is break and combine with sodium to form NaCl through ionic bond.
Explanation:
Chemical equation:
Na + Cl₂ → NaCl
Balanced chemical equation:
2Na + Cl₂ → 2NaCl
The given reaction indicate the formation of sodium chloride.
Sodium chloride is an ionic compound. It is formed by the reaction of chlorine and sodium. The type of bond in Cl₂ is covalent. Both chlorine atoms are tightly held together through sharing of electrons. When sodium chloride is formed the covalent between the chlorine atoms are break and it react with sodium . The chlorine toms thus gain the one electron from the sodium atom and became negative ion while sodium by losing its one valance electrons became positive ions. The strong electrostatic forces are develop between them and ionic bond is formed.
Answer:

Explanation:
Hello,
In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:

In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:

Therefore, the percent yield is:

Best regards.