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Anit [1.1K]
3 years ago
8

Use the diagram and drop-down menus to answer each question.

Chemistry
2 answers:
KATRIN_1 [288]3 years ago
3 0

Answer: circuit B, Circuit A, Circuit B

Explanation:

Edgunity

motikmotik3 years ago
3 0

Answer circuit B circuit A circuit B

Explanation:

i got it on Eng

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Draw the Lewis dot structure for RbIO2. Include all hydrogen atoms and nonbonding electrons. Show the formal charges of all atom
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Answer : The Lewis-dot structure of RbIO_2  is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, RbIO_2

As we know that rubidium has '1' valence electrons, iodine has '7' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in RbIO_2 = 1 + 7 + 2(6) = 20

As we know that RbIO_2  is an ionic compound because it is formed by the transfer of electron takes place from metal to non-metal element.

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