I believe the answer is B!
Answer: pH = 6.77
Explanation:
1) <u>Chemical equilibrium</u>
- 2 H₂O (l) ⇄ H₃O⁺ (aq) + OH⁻ (aq)
2) <u>Equilibrium constant, Kw</u>
- By stoichiometry [H₃O⁺] = [OH⁻]. Call it x
- x = √ (2.92 × 10⁻¹⁴) = 1.709 × 10⁻⁷ M = [H₃O⁺]
3)<u> pH</u>
- pH = - log [H₃O⁺] = - log (1.709 × 10⁻⁷) = 6.77
I think its A: 6-alkane or D:
