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LiRa [457]
3 years ago
11

X-9=13 what should be done to solve the following equation

Mathematics
2 answers:
Vladimir [108]3 years ago
5 0

Answer:

X=22

Step-by-step explanation:

add 9 to both sides

X-9+9=13+9

X=22

Maksim231197 [3]3 years ago
4 0
You do opposite operation. So 9 + 9 = 18. 13 + 9= 22
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I really need help find x in this triangle
arsen [322]

Answer:

x = 5

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 angles and equate to 180

72 + 6x + 2 + 17x - 9 = 180

23x + 65 = 180 ( subtract 65 from both sides )

23x = 115 ( divide both sides by 23 )

x = 5

5 0
3 years ago
150 less than k is 39
d1i1m1o1n [39]

Answer:

your answer is 121

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant
nirvana33 [79]

Answer:

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of y with respect to x over the interval by definition of secant line:

r = \frac{y(b) -y(a)}{b-a} (1)

Where:

a, b - Lower and upper bounds of the interval.

y(a), y(b) - Function exaluated at lower and upper bounds of the interval.

If we know that y = 3\cdot x^{2}, a = 3 and b = 6, then the average rate of change of y with respect to x over the interval is:

r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}

r = 27

The average rate of change of y with respect to x over the interval [3,6] is 27.

b) The instantaneous rate of change can be determined by the following definition:

y' =  \lim_{h \to 0}\frac{y(x+h)-y(x)}{h} (2)

Where:

h - Change rate.

y(x), y(x+h) - Function evaluated at x and x+h.

If we know that x = 3 and y = 3\cdot x^{2}, then the instantaneous rate of change of y with respect to x is:

y' =  \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}

y' =  3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}

y' = 3\cdot  \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}

y' = 6\cdot  \lim_{h \to 0} x +3\cdot  \lim_{h \to 0} h

y' = 6\cdot x

y' = 6\cdot (3)

y' = 18

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

5 0
3 years ago
Given the functions, fx) = x - 8 and g(x) = x2 + x - 1, perform the indicated operation. When applicable, state the domain
adell [148]

Answer:

A

Step-by-step explanation:

(fg)(x) = f(x) × g(x)

= (x - 8)(x² + x - 1)

Each term in the second factor is multiplied by each term in the first factor, that is

x(x² + x - 1) - 8(x² + x - 1) ← distribute both parenthesis

= x³ + x² - x - 8x² - 8x + 8 ← collect like terms

= x³ - 7x² - 9x + 8 → A

There are no restrictions on the domain.

4 0
4 years ago
Please help me with theses 4 questions
MA_775_DIABLO [31]
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2.1640 cm^3
3. 4.0 cm
4. 150pi ft^3
3 0
4 years ago
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