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mafiozo [28]
3 years ago
14

Can someone help me on this please? thanks

Mathematics
2 answers:
patriot [66]3 years ago
8 0
The answers are belowinput:output
0:5
3:14
9:32
yulyashka [42]3 years ago
7 0
The input number is supposed to be substituted for x in the (3x + 5)
so the first one would be (3(0) + 5) = 5
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HELP HELP HELP HELP FIND THE VALUE OF X
aalyn [17]

Answer:

x=9

Step-by-step explanation:

The sum of all three angles inside a triangle is always 180 and the small square in the bottom left corner means that that is a 90 degree angle.

90+5x+5x=180

add the x values together

90+10x=180

subtract 90 from both sides

10x=90

divide both sides by 10

x=9

8 0
3 years ago
Tommy waves 45 kg Jamil Woods 53 kg what is the combined weight of the two boys in grams?
Nikolay [14]

Answer:

109,000

Step-by-step explanation:

1kg = 1000g

45 + 63 = 109

109 x 1000 = 109000

5 0
2 years ago
Help this is due tmw
Zigmanuir [339]
Formula for circumference: 2πr
r=2x+1
C=2π(2x+1)
distribute
C=4πx+2π
3 0
2 years ago
Solve for x. write both solutions, separated by a comma<br> 2x^2-7x-4=0
avanturin [10]
2x^2-7x-4=0

2x^2-8x+x-4=0

2x(x-4)+1(x-4)=0

(2x+1)(x-4)=0

x=-1/2, 4
5 0
3 years ago
Read 2 more answers
Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?
Artemon [7]

Answer:

The equation y=\frac{-x^2-6x+31}{8} represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }, we find that the distance between (x, y) is

\sqrt{(x+3)^2+(y-3)^2}

and the distance between (x, y) and the directrix y = 7 is

\sqrt{(y-7)^2}.

On the parabola, these distances are equal so, we solve for y:

\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}

6 0
3 years ago
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