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2 years ago

A new car is purchased for 17600 dollars. The value of the car depreciates at 11.75%

Mathematics

1 answer:

kramer2 years ago

4 0

Answer:

The value of the car will be

4450.15

Step-by-step explanation:

we know that

11.75%=11.75/100=0.1175

so Let

x-----> the value of the car after 11 years

X=17600(1-0.1175)11=4450.15

Step-by-step explanation:

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Jess will plant up to 27 acres on her farm with wheat and corn. More than 5 acres will be planted with wheat.

Lena [83]

The first thing we do in these cases is to define the variables.
We have then:
w = represent the number of acres of wheat
c = represent the number of acres of corn
We write now the inequalities based is:
"Jess will plant up to 27 acres on her farm with wheat and corn"
w + c <= 27
"More than 5 acres will be planted with wheat"
w> 5
Answer:
two inequalities that represent this situation are:
w + c <= 27
w> 5

8 0

2 years ago

Read 2 more answers

in the year 2012 a farmer harvested 144 bags of maize.the following year the harvest decreased in the ratio 3:4.What was the tot

Alex

Answer:

252 bags of maize

Step-by-step explanation:

From the question, we are told that a farmer harvested maize

In the year 2012 = 144 bags of maize

In the year 2013(following year) the harvest decreased in the ratio 3:4

This means

3:4 = 2013: 2012.

Where number of bags harvested in 2013 = unknown = x

3/4 = x/ 144

Cross multiply 4x = 3 × 144

x = 3 × 144/ 4

× = 108

This means 108 bags of maize was harvested in 2013

The total number of bags harvested is = 108 + 144

= 252 bags of maize.

7 0

2 years ago

Two lighthouses are located 75 miles from one another on a north-south line. If a boat is spotted S 40o E from the northern ligh

yuradex [85]

Answer:

The northern lighthouse is approximately $24.4\; \rm mi$ closer to the boat than the southern lighthouse.

Step-by-step explanation:

Refer to the diagram attached. Denote the northern lighthouse as $\rm N$ , the southern lighthouse as $\rm S$ , and the boat as $\rm B$ . These three points would form a triangle.

It is given that two of the angles of this triangle measure $40^{\circ}$ (northern lighthouse, $\angle {\rm N}$ ) and $21^{\circ}$ (southern lighthouse $\angle {\rm S}$ ), respectively. The three angles of any triangle add up to $180^{\circ}$ . Therefore, the third angle of this triangle would measure $180^{\circ} - (40^{\circ} + 21^{\circ}) = 119^{\circ}$ (boat $\angle {\rm B}$ .)

It is also given that the length between the two lighthouses (length of $\rm NS$ ) is $75\; \rm mi$ .

By the law of sine, the length of a side in a given triangle would be proportional to the angle opposite to that side. For example, in the triangle in this question, $\angle {\rm B}$ is opposite to side $\rm NS$ , whereas $\angle {\rm S}$ is opposite to side ${\rm NB}$ . Therefore:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of NB}}{\sin(\angle {\rm S})} \end{aligned}$ .

Substitute in the known measurements:

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of NB}}{\sin(21^{\circ})} \end{aligned}$ .

Rearrange and solve for the length of $\rm NB$ :

$\begin{aligned} & \text{length of NB} \\ =\; & (75\; \rm mi) \times \frac{\sin(21^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 30.73\; \rm mi\end{aligned}$ .

(Round to at least one more decimal places than the values in the choices.)

Likewise, with $\angle {\rm N}$ is opposite to side ${\rm SB}$ , the following would also hold:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of SB}}{\sin(\angle {\rm N})} \end{aligned}$ .

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of SB}}{\sin(40^{\circ})} \end{aligned}$ .

$\begin{aligned} & \text{length of SB} \\ =\; & (75\; \rm mi) \times \frac{\sin(40^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 55.12\; \rm mi\end{aligned}$ .

In other words, the distance between the northern lighthouse and the boat is approximately $30.73\; \rm mi$ , whereas the distance between the southern lighthouse and the boat is approximately $55.12\; \rm mi$ . Hence the conclusion.