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zvonat [6]
3 years ago
8

Which expressions are equivalent to 25x4 −64? Select three options. 25x4 + 40x − 40x − 64 25x4 + 13x − 13x − 64 (5x2 + 8)(5x2 −

8) (x2 + 13)(x2 – 13) (5x2 – 8)2
Mathematics
2 answers:
Lana71 [14]3 years ago
7 0

Answer:

a, b, c

25x4 + 40x − 40x − 64, 25x4 + 13x − 13x − 64, (5x2 + 8)(5x2 − 8)

Step-by-step explanation:

exis [7]3 years ago
5 0

Answer:

The equivalent expression of 25 - 64 are "a), b) and c)"

Step-by-step explanation

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Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten
Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

Q(t) = Q(0)e^{-rt}

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that Q(12) = 0.5Q(0)

So

Q(t) = Q(0)e^{-rt}

0.5Q(0) = Q(0)e^{-12r}

e^{-12r} = 0.5

\ln{e^{-12r}} = \ln{0.5}

-12r = \ln{0.5}

12r = -\ln{0.5}

r = -\frac{\ln{0.5}}{12}

r = 0.05776

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

Q(t) = Q(0)e^{-rt}

50 = 200e^{-0.05776t}

e^{-0.05776t} = 0.25

\ln{e^{-0.05776t}} = \ln{0.25}

-0.05776t = \ln{0.25}

0.05776t = -\ln{0.25}

t = -\frac{\ln{0.25}}{0.05776}

t = 24

It would take 24 minutes for the element to decay to 50 grams

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4 years ago
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12x12 + 12x12 = 288 = root of 288= 16.97
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