Distance and displacement are hardly ever equal.
Remember that 'displacement' is the straight-line distance between
the start-point and the end-point, regardless of what path you followed
on the way.
So they're equal ONLY when the trip from start to finish was completely
in a straight line.
Answer:
Inclined Plane - A ramp, for example a wheelchair ramp to help move to another level.
Wheel & Axle - On lawnmowers and wheelbarrow.
Lever - A seesaw
Pulley - adjustable clothesline (think from back then when you would put clothes out to dry them)
Screw - the bottle caps you screw on or off
Answer:
2.04m/s²
Explanation:
Complete Question
<em>A stationary 10 kg object is located on a table near the surface of the earth. The coefficient of kinetic friction between the surfaces is 0.2. A horizontal force of 40 N is applied to the object. Find the acceleration of the object.</em>
<em />
According to Newtons second law;
\sum F_x = ma_x
F_m - F_f = ma_x
Fm is the applied force
Ff is the frictional force
m is the mass
a is the acceleration
Substitute the given values
40N - nmg = 10a
40 - 0.2(10)(9.8) = 10a
40 - 19.6 = 10a
20.4 = 10a
a = 20.4/10
a = 2.04m/s²
<em>Hence the acceleration of the object is 2.04m/s²</em>
Answer:
The height of the object is 50 feet
Explanation:
Given that:
The path of an object projected at a 45 degree angle with initial velocity of 80 feet per second is given by the function ![h (x) =\dfrac{-32}{(80)^2}x^2+x](https://tex.z-dn.net/?f=h%20%28x%29%20%3D%5Cdfrac%7B-32%7D%7B%2880%29%5E2%7Dx%5E2%2Bx)
where;
x is the horizontal distance traveled and h(x) is the height in feet.
The objective is to use the TRACE feature of your calculator to determine the height of the object when it has traveled 100 feet away horizontally.
Before then;
If the function ![h (x) =\dfrac{-32}{(80)^2}x^2+x](https://tex.z-dn.net/?f=h%20%28x%29%20%3D%5Cdfrac%7B-32%7D%7B%2880%29%5E2%7Dx%5E2%2Bx)
and x = 100
then :
![h (x) =\dfrac{-32}{(80)^2}(100)^2+100](https://tex.z-dn.net/?f=h%20%28x%29%20%3D%5Cdfrac%7B-32%7D%7B%2880%29%5E2%7D%28100%29%5E2%2B100)
![h (x) =\dfrac{-32}{6400} \times 10000+100](https://tex.z-dn.net/?f=h%20%28x%29%20%3D%5Cdfrac%7B-32%7D%7B6400%7D%20%5Ctimes%2010000%2B100)
![h (x) =- 0.005 \times 10000+100](https://tex.z-dn.net/?f=h%20%28x%29%20%3D-%200.005%20%5Ctimes%2010000%2B100)
![h (x) =- 50+100](https://tex.z-dn.net/?f=h%20%28x%29%20%3D-%2050%2B100)
h(x) = 50 feet
Using the TRACE CALCULATOR,
In your Trace calculator;
input Y = X - 32 X^2/(80) this because in the calculator Y denotes h(x)
Now over to the WINDOW
set the window as follows:
Xmin = 0
Xmax = 200
Xsc1 =1
Ymin = 0
Ymax = 50
Ysc = 1
Xres = 1
After that, click on the graph key and an output will display as seen in the image below.
Therefore, the show the value of Y which we earlier said it denotes the h(x) = 50 feet