An electric dipole consists of a particle with a charge of 6 x 10⁻⁶ c at the origin and a particle with a charge of –6 x 10⁻⁶ c on the x axis at x = 3 x 10⁻³ m. Its dipole moment is 18 x 10⁻⁹ Cm
Dipole moment of a dipole is dependent on the charge of the dipole and the distance between the two charges.
Electric Dipole consists of two charges which are equal and opposite in charge i.e. positive and negative charges.
Given,
Dipole moment, p = ?
Charge, q = 6 x 10⁻⁶C
Distance between charges, d = 3 x 10⁻³ m
Dipole moment (p) is given by:
p = charge x distance between the two charges
p = 6 x 10⁻⁶ x 3 x 10⁻³ Cm
p = 18 x 10⁻⁹ Cm
The dipole moment for the given charge configuration is 18 x 10⁻⁹ Cm
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D= vt +.5at^2
since he started at rest, v (initial velocity) is 0
so d=.5at^2
d = .5 (6m/s^2) (4.1s)^2
then put that into a calculator.
Answer:
you can build a mote around your castle and put crocodiles in it.
Explanation:
they will have to go in the water to get to your castle and will get eaten.
Answer:
Stretch can be obtained using the Elastic potential energy formula.
The expression to find the stretch (x) is 
Explanation:
Given:
Elastic potential energy (EPE) of the spring mass system and the spring constant (k) are given.
To find: Elongation in the spring (x).
We can find the elongation or stretch of the spring using the formula for Elastic Potential Energy (EPE).
The formula to find EPE is given as:

Rewriting the above expression in terms of 'x', we get:

Example:
If EPE = 100 J and spring constant, k = 2 N/m.
Elongation or stretch is given as:

Therefore, the stretch in the spring is 10 m.
So, stretch in the spring can be calculated using the formula for Elastic Potential Energy.
Answer:
12 km/h
Explanation:
Average Speed = Distance / Time (or rate)
Pick a point on the graph for Ian and plug in values.
For example, 20 minutes -> 4km
Hence, Average speed = 4km ÷ 20 minutes = 0.2 km/min
0.2 km/min × 60 = 12 km/h