The maximum height reached by the ball is 99.2 m
Explanation:
When the ball is thrown straight up, it follows a free fall motion, which is a uniformly accelerated motion with constant acceleration ( towards the ground). Therefore, we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
In this problem, we have:
u = 44.1 m/s is the initial vertical velocity of the ball
v = 0 is the final velocity when the ball reaches the maximum height
s is the maximum height
is the acceleration of gravity (downward, so negative)
Solving for s, we find the maximum height reached by the ball:
Learn more about free fall:
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Answer:
82.1 km
Explanation:
We need to resolve each displacement along two perpendicular directions: the east-west direction (let's label it with x) and the north-south direction (y). Resolving each vector:
Vector B is 48 km south, so:
Finally, vector C:
Now we add the components along each direction:
So, the resultant (which is the distance in a straight line between the starting point and the final point of the motion) is
Answer:
0.25miles/min
Explanation:
Instantaneous speed of a person or an object is its speed at a particular moment usually at a period of time.
The speedometer of a car reports the instantaneous speed.
It can be mathematically expressed as;
Instantaneous speed =
At 20min the distance covered is 5miles;
Instantaneous speed = = 0.25miles/min
Answer:
- 600 J
Explanation:
A (20, 15, 0 ) m
B (0, 0, 7) m
Net force
Work done is defined as
W = -1120 + 450 + 70
W = - 600 J