Which compound is an exception to the octet rule? H2O OHCI OCCIA CIF3

Assuming that a chemical reaction doubles in rate for each 10° temperature increase, by what factor would the rate increase if t

12345 [234]

Answer:

It'll be increased by a factor of 16...

Explanation:

After 10 C = Doubles

After 20 C = 4 Times

After 30 C = 8 Times

After 40 C = 16 Times

(The rate of reaction doubles as per 10 C rise in temperature as calculated)

6 0

3 years ago

A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0

3 years ago

Read 2 more answers

Which of the following is the best definition of convection?

lara [203]

a) movement of heat through space

7 0

3 years ago

Read 2 more answers

Which wave has a disturbance that is perpendicular to the wave motion?

Otrada [13]

It B I just took the test ;)

7 0

4 years ago

Read 2 more answers

Is the equation below balanced? Explain your answer. Zn(OH)2 + NaOH → Na2ZnO2 + H2O

iren2701 [21]

Answer:

No, it is not balanced.

The balanced equation is: Zn(OH)₂ + 2NaOH → Na₂ZnO₂ + 2H₂O.

Explanation:

To balance the equation, you should apply the law of conservation of mass for the equations.

The law of conservation of mass states that the no. of each atom is equal in both sides (reactants and products).

For the given equation: Zn(OH)₂ + NaOH → Na₂ZnO₂ + H₂O.

The no. of Na atoms in reactants side is 1 but in products side is 2.

The no. of H atoms in reactants side is 3 but in product side is 2.

So, the equation is not balanced.

The balanced equation is:

Zn(OH)₂ + 2NaOH → Na₂ZnO₂ + 2H₂O.

The no. of all atoms is the same in both of reactants and products side.

Zn (1), O (4), H (4), and Na (2).

7 0

4 years ago