Can someone help me with this problem please
2 answers:
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Answer:
3600 gallons of water was removed from the basement.
Step-by-step explanation:
Given:
Rate of each pump = 40 gallons/min
We need to find find the number of gallons of water removed from the basement.
Solution:
Now Given:
After half an hour, the one pump burns out.
Now we know that;
1 hour = 60 mins
hour =
Now for 30 mins both the pumps were working and removing the water.
So we can say that;
Water remove for first 30 mins =
Also Given:
the second pump finishes removing the water half an hour later.
So we can say that;
Water removed for next 30 mins =
Now we can say that;
Total water removed from the basement is equal to sum of Water remove for first 30 mins and Water removed for next 30 mins .
framing in equation form we get;
Total water removed from the basement =
Hence 3600 gallons of water was removed from the basement.
Answer:
(a) 8.15
(b) 12.92
Step-by-step explanation:
Given: P = $3000, r = 0.085
Where
A is the Amount
P is the Principal
r is the rate
t is the time
(a) For the amount to double, A = 2 × P
A = 2 × $3000
A = $6000
Take of both sides
But
∴
t = 8.15
(b) For the amount to double, A = 3 × P
A = 3 × $3000
A = $9000
Take of both sides
But
∴
t = 12.92