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2 years ago

In a class. 40% of the student's study math and science, 60% of the students study

Mathematics

1 answer:

GaryK [48]2 years ago

8 0

Answer:

2/3

Step-by-step explanation:

A = Student studying Math

B = Student studying Science

P(B|A) = P(A and B) ÷ P(A).

P(B|A) means the probability of event B given event A.

Given :

P(A and B) = 0.40.

Also P(A) = 0.60.

P(B|A) = 0.40 ÷ 0.60 = 2 ÷ 3.

So, the answer is 2/3.

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Let U = {1, 2, 3, 4, 5, 6), A = {1, 2, 3, 4), and B = {1, 2, 4). Find the set A n B.

PSYCHO15rus [73]

Step-by-step explanation:

(A n b) = this means that we need d value that is in a and b only

ans= (1,2,4)

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2 years ago

The equation,y = 225x + 200, represents the cost,y, students must pay to play x sports, as long as the athlete's family has join

Ira Lisetskai [31]

Answer:

The answer is B I am on the time for learning format so It may differ but for me it's B

Step-by-step explanation:

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2 years ago

Every 4 seconds, a ski lift chair rises 14 feet. Describe the relationship between the height of the chair and the time.

Svetradugi [14.3K]

Answer

Everything will increase.

Step-by-step explanation:

According to the question, the chair rises every 4 seconds 14 feet high. Therefore, the relationship between the chair and time is: the chair rises every 4 seconds.

Feel free to copy it I don't mind :)

8 0

3 years ago

Please solve these questions for me. i am having a difficult time understanding.

s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

$\angle AED = \angel BEC$ ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

Refer the attached figure

$\angle ABC = 90^{\circ}$

In ΔDBC

BC=DC (Given)

So, $\angle CDB=\angle DBC$ (Opposite angles of equal sides are equal)

So, $\angle CDB=\angle DBC=x$

So, $\angle CDB+\angle DBC+\angle BCD = 180^{\circ}$ (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So, $\angle CDB=\angle DBC=x = 65^{\circ}$

Now,

$\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90$

So, $\angle ABD=90-x=90-65=25^{\circ}$

In ΔABD

AB = BD (Given)

So, $\angle BAD=\angle BDA$ (Opposite angles of equal sides are equal)

So, $\angle BAD=\angle BDA=y$

So, $\angle BAD+\angle BDA+\angle ABD = 180^{\circ}$ (Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0

3 years ago

Help pleaseee :)!!!!!!!!!

harkovskaia [24]

Answer:

5x/x+3

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask!

3 0

3 years ago

Read 2 more answers