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3 years ago

14

Possible my last brainliest if its right question idk may be more but this one is harsh for me

1 answer:

adelina 88 [10]3 years ago

4 0

Correct Solution: He read 1.5 pages per minute.

Error Analysis: You should’ve divided 3 by 2 not 300. There are 300 pages in the book total. This information is irrelevant to the question. Cole reads 3 pages in two minutes. So you divide 3 by to to find out how many pages he reads per minute. 3/2=1.5

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The table show the age in years of employees in a company

adelina 88 [10]

Answer:

A. 24 ≤ a < 26.

B. 22.5

Step-by-step explanation:

A. Determination of the modal class interval.

Mode is the class with the highest frequency.

From the table given above, the highest frequency is 8, therefore the class will the highest frequency is:

24 ≤ a < 26.

B. To obtain the mean, we must determine the class mark. This is illustrated below:

Class >>>>> class mark >>> frequency

18 – 19 >>>> 18.5 >>>>>>>>> 3

20 – 21 >>> 20.5 >>>>>>>> 2

22 – 23 >>> 22.5 >>>>>>>> 7

24 – 25 >>> 24.5 >>>>>>>> 8

26 >>>>>>>> 26 >>>>>>>>> 0

The mean is given by the summation of the product of the class mark and frequency divided by the total frequency. This is illustrated below:

Mean = [(18.5x3) + (20.5x2) + (22.5x7) + (24.5x8) + (26x0)] / (3+2+7+8+0)

Mean = (55.5 + 41 + 157.5 + 196 + 0)/20

Mean = 450/20

Mean = 22.5

Therefore, the mean age is 22.5

4 0

3 years ago

Read 2 more answers

A spherical balloon is being inflated at a rate of 3 cubic inches per second. Determine the change in the rate of the radius.How

Novay_Z [31]

Answer:

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

The radius is changing more rapidly when the diameter is 12 inches.

Step-by-step explanation:

Consider the provided information.

A spherical balloon is being inflated at a rate of 3 cubic inches per second.

The volume of sphere is $V=\frac{4}{3}\pi r^3$

Differentiate the above formula with respect to time.

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

Substitute the respective values in the above formula,

$3=4\pi 6^2\frac{dr}{dt}$

$\frac{1}{48\pi}=\frac{dr}{dt}$

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

When d=16

$3=4\pi 8^2\frac{dr}{dt}$

$\frac{3}{256\pi}=\frac{dr}{dt}$

Thus, the radius is changing more rapidly when the diameter is 12 inches.

5 0

3 years ago

I need help with this question?

babymother [125]

The correct answer is C.

8 0

3 years ago

Solve for x.<br><br> −5x−4(x−6)=−3

zvonat [6]

- 5x - 4x + 24 = - 3
9x = 27
x = 3

3 0

3 years ago

Find two different 2 by 2 matrices a and b such that ab=ba

stiv31 [10]

Let $\mathbf A=\mathbf I$ be the identity matrix. Then pick whatever matrix you like for $\mathbf B$ .

8 0

3 years ago