2<span>(<span>log4</span><span>(3)</span>+<span>log4</span><span>(x)</span>+<span>log4</span><span>(y)</span>+<span>log4</span><span>(z)</span><span>)</span></span>
Hmm. Try counting the side of the shape and add the sides. Using the sides as numbers you may be able to solve the problem.
To solve, substitute the values of x with 2.
(2)^1 - (2) - 1 + 2^0 = 0.
The answer would be a)
Answer:
Option (1)
Step-by-step explanation:
From the picture attached,
Triangle CAB is a right triangle.
Therefore, m∠1 = 90°
Similarly, m∠ACD = 90°
m∠ACD = m∠ACB + m∠BCD = 90°
= m∠3 + m∠4 = 90°
Since m∠4 = 35°,
m∠3 + 35° = 90°
m∠3 = 90° - 35°
= 55°
In the triangle ABC,
m∠ACB + m∠CBA + m∠BAC = 180° [Property of a triangle]
m∠3 + m∠2 + m∠1 = 180°
55° + m∠2 + 90° = 180°
m∠2 + 145° = 180°
m∠2 = 180° - 145°
= 35°
Since, AB║CD and BC is a transverse,
Therefore, m∠2 = m∠4 = 35° [Alternate interior angles]
Option (1) is the correct option.
A calculator can show you the answer to these very quickly.
