Answer:
Step-by-step explanation:
<u><em>Part B:</em></u>
The center of the circumscribed circle around a triangle is equidistant from vertices of that triangle. To find the circumcenter need to draw at least two perpendicular bisectors to the sides of the given triangle. Point of intersect of them is center of the circumscribed circle.
<u><em>Part C:</em></u>
Coordinates of the midpoint of line BC ( y = - 1 ) are
( 
, 
) = <em>( - 2 , - 1 )</em> and the equation of the line ⊥ to BC is <em>x = - 2</em>
Because BC is ║ to x-axis and m∠A is 90° , the center of the circle is midpoint of BC and r = 
= 4
Answer:
i will
Step-by-step explanation:
Answer: (m-1)(m-8)
Hope this helps
What is the question? I don't understand please explain?
<h3>
Answer: Choice B</h3>
Angle 1 = 147 degrees
Angle 2 = 80 degrees
Angle 3 = 148 degrees
======================================================
Work Shown:
(angle 1) + 33 = 180
angle 1 = 180-33
angle 1 = 147 degrees
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Focus on the left most triangle that has angles 33 and 47 as interior angles. The missing angle is 180-33-47 = 100 degrees
The angle exterior to this 100 degree angle is angle 2
angle 2 = 180-100 = 80
We have enough info to conclude the answer must be choice B.
---------------
Let's keep going to find angle 3
The vertical angle for the 100 degree angle is also 100 degrees. This second 100 degree angle is part of the triangle on the right
This triangle on the right has interior angles 100 and 48
The missing interior angle is 180-100-48 = 32
The angle supplementary to this is 180-32 = 148, which is angle 3.
