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2 years ago

Which expression is equivalent to 7m + 5 + 6 + 3m?

Mathematics

2 answers:

bazaltina [42]2 years ago

4 0

Answer:

10m + 11

Step-by-step explanation:

7m + 5 + 6 + 3m

7m + 3m = 10m

5 + 6 = 11

10m + 11

Lisa [10]2 years ago

3 0

Answer:

10m+11

Step-by-step explanation:

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Figure BCDE was transformed using the composition rx-axis ◦ T2,2. If point B on the pre-image lies at (3, 4), what are the coord

____ [38]

Answer:

The answer is "(5, -6)"

Step-by-step explanation:

Given:

The Pre-image line at point B is: (3, 4)

Solution:

$\ rx-axis \circ \ T2,2 (3,4) \\\\\Rightarrow \ rx-axis \ ( T2,2 (3,4) )\\\\ \Rightarrow \ rx-axis ( 5,6 ) \\\\ \Rightarrow (5, -6)\\$

The coordinates of B point is (5,-6).

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3 years ago

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Refer to scenario 4. assume that the profit equation is $110x1 + $150x2 what is the profit at corner point (0, 30)?

SashulF [63]

If you have the profit formula which is profit (x1, x2) = 110x1 + 150x2, then by substitution of the given point (x1, x2) = (0, 30), you can find the profit at the corner point profit (0.30 ) = 110 (0) + 150 (30) = 4500.Therefore the profit will be $ 4500

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3 years ago

HELP ME PLEASE!!!!

horsena [70]

$2\sqrt5+3\sqrt5-\sqrt5=(2+3-1)\sqrt5=4\sqrt5\\\\\text{Answer:}\ 4\sqrt5$
Look at the square root like "x", then
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3 0

3 years ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

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2 years ago

What is the solution for x in the equation? 9 - 10x2x+1-8x x = ?

LUCKY_DIMON [66]

Answer:

-3x

Step-by-step explanation:

this is the answer I think

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2 years ago