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Drupady [299]
3 years ago
13

How can you help fight climate change in your daily life?​

Chemistry
1 answer:
defon3 years ago
8 0

Answer:

Explanation:

You could ride a bike not use bottled water you could try and use solar energy.

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Britney added 0.05 moles of copper(II) nitrate solution to 0.1 moles of sodium hydroxide solution and
Rama09 [41]

The percent yield of copper hydroxide is 84%

<h3>Stoichiometry</h3>

From the question, we are to determine the percent yield of copper hydroxide

First, we will determine the theoretical mass

From the given balanced chemical equation, we have

Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃

This means,

1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide

Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide

The theoretical number of moles of copper hydroxide that is produced is 0.05 mole

Now, for the theoretical mass

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of copper hydroxide = 97.56 g/mol

Then,

Theoretical mass = 0.05 × 97.56

Theoretical mass of copper of hydroxide produced is = 4.878 g

Now, for the percent yield of copper hydroxide

Percent yield is given by the formula,

Percent\ yield = \frac{Actual\ yield}{Theoretical\ yield} \times 100\%

Then,

Percent\ yield\ of\ copper\ hydroxide= \frac{4.1}{4.878}\times 100\%

Percent\ yield\ of\ copper\ hydroxide= 84\%

Hence, the percent yield of copper hydroxide is 84%.

Learn more on Stoichiometry here: brainly.com/question/9372758

7 0
3 years ago
A disturbance that transfers energy from one place to another without transferring matter
Stolb23 [73]

Answer:

Hi Im an online tutor and i can assist you with all your assignments. We have experts in all fields. check out our website https://toplivewriters.com

Explanation:

8 0
3 years ago
What mass of calcium hydroxide is formed when 10.0g of calcium oxide reacts with 10.0g of water?
nexus9112 [7]

The mass of calcium hydroxide that is formed when 10.0 g of CaO reacts with  10.0 g of water is 13.024 grams


calculation

from the equation

CaO + H2O → Ca(OH)2,

 1 moles of CaO reacted with 1 moles of H2O to form 1 moles of Ca(OH)2

find the moles of each reactant

moles=mass/molar mass

moles of CaO= 10 g/56 g/mol=0.179 moles

moles of H2O = 10 g/18 g/mol 0.556  moles

CaO is the limiting reagent  therefore by use of mole ratio of CaO:Ca(OH)2 which is 1:1 moles of Ca(OH)2 is = 0.179 moles

mass= moles x molar mass

= 0.176 moles x  74 g/mol = 13.024  grams

7 0
4 years ago
Answer this correctly, only sincere answers please. I really need help. I will do all I can to make someone answer this. Thanks!
Marrrta [24]

Answer:

See Explanation

Explanation:

Let us recall that;

[H^+] [OH^-] = 1 * 10^-14

Where;

[OH^-] = 1 x 10^-11

Then;

[H^+] = 1 * 10^-14/1 x 10^-11

[H^+] = 1 * 10^-3

pH = -log [H^+]

pH = -log(1 * 10^-3)

pH = 3

Also;

pH + pOH = 14

pOH = 14 - pH

pOH = 14 -3

pOH = 11

8 0
3 years ago
Under conditions of "feasting", the body favors oxidation/utilization of which source for energy production
mezya [45]
During feasting, there is an increase in the supply of carbohydrates, fats and proteins in the body. Since these macronutrients are in excess, carbohydrates and proteins are utilized or oxidized as a source for energy production. On the otherhand, fats are accumulated as the rate of oxidation of this source does not increase during feasting. 


4 0
4 years ago
Read 2 more answers
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