What are the zeros of this function?
1 answer:
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We have that
<span>p(t)=-3t^2+18t-4
using a graphing tool, we can see the maximum of the graph
(see the attached figure)
A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?
</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)
<span>B) What is the maximum profit?
23 (hundred of thousand of dollars) = 2.300.000 dollars
</span>c) What time will it be two late?
(This is the time when the graph crosses zero and the profits turn into losses )
5.77 years, or an estimate of about 69 months.
<span>p(t)=-3t^2+18t-4
using a graphing tool, we can see the maximum of the graph
(see the attached figure)
A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?
</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)
<span>B) What is the maximum profit?
23 (hundred of thousand of dollars) = 2.300.000 dollars
</span>c) What time will it be two late?
(This is the time when the graph crosses zero and the profits turn into losses )
5.77 years, or an estimate of about 69 months.
Step-by-step explanation:
Hey there!
By looking through figure, l and m are parallel lines and a transversal line passes through the lines.
Now,
7x + 12° = 12x - 28°( alternate angles are equal)
12°+28° = 12x - 7x
40° = 5x
Therefore, x = 8°
Now,
12x - 28° + 9y - 77 = 180° ( being linear pair)
12×8° - 28° + 9y -77° = 180°
96° - 28° + 9y - 77° = 180°
-9 + 9y = 180°
9y = 180° + 9°
y = 189°/9
Therefore, y = 21°
<u>There</u><u>fore</u><u>,</u><u> </u><u>X </u><u>=</u><u> </u><u>8</u><u>°</u><u> </u><u>and</u><u> </u><u>y</u><u>=</u><u> </u><u>2</u><u>1</u><u>°</u><u> </u><u>.</u>
<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>