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Strike441 [17]
3 years ago
15

The logo on a shirt is in the shape of a parallelogram. What is the area of the parallelogram? Round to the nearest tenth.

Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0

Answer:

90

Step-by-step explanation:

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HELP PLEASE I HAVE A COUPLE MORE! Please help and fast would be great! BRAINLEST!!!
Harlamova29_29 [7]

Answer:

b. slope: -5; y-intercept: 7

Step-by-step explanation:

We are given the equation:

y + 5x = 7

To find the slope and y-intercept of the line, it would be helpful to get the equation into slope-intercept form. The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the y-intercept.

Lets get the given equation into slope-intercept form.

y + 5x = 7

Subtract 5x from both sides.

y = -5x + 7

Now we have the equation in slope-intercept form. By looking at the equation, we can see that the slope is -5 and that the y-intercept is 7.

The correct answer choice would be b.

I hope you find my answer and explanation to be helpful. Happy studying.

3 0
3 years ago
i am begging for help. all of my points for the first to answer. The volume of a sphere is 3/4 x pi cm^3. what is the radios of
horsena [70]

volume of a sphere = 4/3 *pi * r^3

3/4 * pi = 4/3 *pi * r^3

divide each side by pi

3/4 = 4/3 * r^3

multiply each side by 3/4

3/4 * 3/4 = r^3

9/16 = r^3

take the cube root of each side

r = (9/16) ^ (1/3)

3 0
3 years ago
When graphed, which function has a horizontal asymptote at 4?
Agata [3.3K]

Answer:

C sorry if its wrong

Step-by-step explanation:

6 0
3 years ago
Solve the following system of equations.<br> y = 2x + 1<br> y = x2 – 5x + 7
BlackZzzverrR [31]

The answer is x = 2 and y = 3

5 0
3 years ago
Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.
natali 33 [55]

Answer:

The solution of the given initial value problems in explicit form is y=x-x^2-2  and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

y'=1-2x

It can be written as

\frac{dy}{dx}=1-2x

Use variable separable method to solve this differential equation.

dy=(1-2x)dx

Integrate both the sides.

\int dy=\int (1-2x)dx

y=x-2(\frac{x^2}{2})+C                  [\because \int x^n=\frac{x^{n+1}}{n+1}]

y=x-x^2+C              ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

-2=1-(1)^2+C

-2=1-1+C

-2=C

The value of C is -2. Substitute C=-2 in equation (1).

y=x-x^2-2

Therefore the solution of the given initial value problems in explicit form is y=x-x^2-2 .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

4 0
3 years ago
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