Low melting point and poor conductor of electricity

A sample of seawater consists of water, sodium ions, chloride ions, and several other dissolved salts. These ions and salts are

stellarik [79]

Answer:

Mixture, homogeneous mixture, solution

Explanation:

A mixture is defined as a substance which is made by physical combination of two or more substance.

As in sea water, more than two substance are present, therefore is considered as mixture.

A mixture is considered as homogeneous mixture, if it has same proportion of components through out the mixture. In sea water proportions of all the components are same, therefore, its is also a homogeneous mixture.

In solution, solute is dissolved in a solvent and the concentration of the solute is same through out the solution.. In sea water, sodium ions, chloride ions, and several other salts are dissolved in water. Therefore, water is considered as solvents and components present are considered as solute.

so, sea water can also considered as solution.

Among the given options, 1, 3 and 4 are correct

So, sea water is considered as mixture, homogeneous mixture and solution.

6 0

3 years ago

The pressure of a sample of helium in a 200. ml. container is 2.0 atm. If the 5 points

just olya [345]

The pressure of the gas = 40 atm

<h3>Further explanation</h3>

Given

200 ml container

P = 2 atm

final volume = 10 ml

Required

Final pressure

Solution

Boyle's Law

At a fixed temperature, the gas volume is inversely proportional to the pressure applied

$\tt \rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}$

Input the value :

P₂ = P₁V₁/V₂

P₂ = 2 x 200 / 10

P₂ = 40 atm

3 0

3 years ago

rite stepwise equations for protonation or deprotonation of this polyprotic species in water. What are the products of the first

adoni [48]

<u>Answer:</u> The products of the given chemical equation are $HCO_3^-\text{ and }OH^-$

<u>Explanation:</u>

Protonation equation is defined as the equation in which protons get added in the substance.

The chemical equation for the protonation of carbonate ion in the presence of water follows:

$CO_3^{2-}+H_2O\rightarrow HCO_3^-+OH^-$

By Stoichiometry of the reaction:

1 mole of carbonate ion reacts with 1 mole of water to produce 1 mole of hydrogen carbonate ion and 1 mole of hydroxide ion

Hence, the products of the given chemical equation are $HCO_3^-\text{ and }OH^-$

3 0

3 years ago

After throwing the ball in the pool for my dog the ball sprung a leak and begin to fill with water. How many mL of water can th

ikadub [295]

Answer: i think 250ML

Explanation:

5 0

3 years ago

1 poin

8090 [49]

Answer:

It's called Independent variable

Explanation:

....

4 0

3 years ago