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4 years ago

11

Im chemistry we are solving chemical reactions and on the assignments our teacher put the questions as riddels and I can not get

this one:
What can you "THROW" and not "CATCH"?

What is the answer?

1 answer:

lara31 [8.8K]4 years ago

6 0

Are they trying to be funny about it?

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The Keq for the equilibrium below is 5.4 × 1013 at 480.0 °C. 2NO (g) + O2 (g) 2NO2 (g) What is the value of Keq at this temperat

kodGreya [7K]

<u>Answer:</u> The equilibrium constant for $NO_2(g)\rightleftharpoons NO(g)+\frac{1}{2}O_2(g)$ equation is $1.36\times 10^{-7}$

<u>Explanation:</u>

The given chemical equation follows:

$2NO(g)+O_2(g)\rightleftharpoons 2NO_2(g)$

The value of equilibrium constant for the above equation is $K_{eq}=5.4\times 10^{13}$

Calculating the equilibrium constant for the given equation:

$NO_2(g)\rightleftharpoons NO(g)+\frac{1}{2}O_2(g)$

The value of equilibrium constant for the above equation will be:

$K'_{eq}=\frac{1}{\sqrt{K_{eq}}}\\\\K'_{eq}=\frac{1}{\sqrt{5.4\times 10^{13}}}\\\\K'_{eq}=1.36\times 10^{-7}$

Hence, the equilibrium constant for $NO_2(g)\rightleftharpoons NO(g)+\frac{1}{2}O_2(g)$ equation is $1.36\times 10^{-7}$

5 0

3 years ago

How much heat is absorbed/released when 20.00 g of NH3(g) (17.0307g/mol) react in the presence of excess O2(g) to produce NO(g)

irina1246 [14]

Answer:

342.8 kJ are absorbed

Explanation:

In the reaction:

4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l) ΔH° = 1168 kJ

<em>As ΔH > 0, the heat is absorbed. Also, when 4 moles of NH3 are involved in the reaction, there are absorbed 1168 kJ</em>.

Having this in mind, moles of NH3 in 20.00g are:

20.00g × (1mol / 17.0307g) = <em>1.174 moles</em>

<em></em>

Thus, 1.174 moles of NH3 absorbed:

1.174 moles × (1168 kJ / 4 moles) = <em>342.8 kJ are absorbed</em>.

8 0

4 years ago

Which of the following is most likely a homogeneous mixture?

Dmitry [639]

Answer:

D)A vanilla milkshake

Explanation:

8 0

3 years ago

Read 2 more answers

What is the total number of moles of naoh needed to react

Elza [17]

4 because he needed to see

6 0

3 years ago

1. How many grams are there in 7.5 x 1023 molecules of H2SO4?

Karo-lina-s [1.5K]

Answer:

I cannot give you all the answer but I can help you to solve those.

Explanation:

The first question:

How many grams are there in 7.5× $10^{23}$ molecules of $H_{2} SO_{4}$ ?

So we need to find the molecular mass first, use your periodic table,

And then we can find out 2+32+16×4=98 g/mol

Then, we need to find how many moles, by using Avogadro's constant:

Avogadro's constant: 1 mole = 6.02× $10^{23}$

∴ $\frac{7.5*10^{23} }{6.02*10^{23}}$ =1.25 mol(2d.p.)

Lastly, find the grams using the formula $M= \frac{m}{n}$

m=Mn

m=1.25*98

m=122.5g

-------------------------------------------------------------------------------------------------------------

In conclusion, use those formula to help you:

$M= \frac{m}{n}$ (which M = molecular mass(atomic mass) m=mass of the substance and n = moles)

Avogadro's constant: $\frac {molecular mass} {6.02*10^{23}} = moles$

5 0

3 years ago