Answer:
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Answer:
4Fe + 3O₂ → 2Fe₂O₃
General Formulas and Concepts:
<u>Chemistry - Reactions</u>
Explanation:
<u>Step 1: Define</u>
RxN: Fe + O₂ → Fe₂O₃
<u>Step 2: Balance</u>
We need to balance both Fe and O.
LCM of 2 and 3 is 6:
Fe + 3O₂ → 2Fe₂O₃
We now need the same amount of Fe on both sides:
4Fe + 3O₂ → 2Fe₂O₃
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Answer:
in my opinion find some stuff to help u with it test if you are aloud to bring in a revision boom into your test and get a good night sleep if you can and try not to get stressed about it
Answer:
Explanation:
How many mols do you have?
1 mol = 6.02 * 10^23 atoms
x mol = 6.25 * 10 ^32 atoms
1/x = 6.02*10^23 / 6.25 * 10^32 Cross multiply
6.02 * 10^23 * x = 1 * 6.25 * 10^32 Divide by 6.02 * 10^23
x = 6.25 * 10*32/ 6.02 ^10^23
x = 1.038 * 10^9 mols which is quite large.
Find the number of grams. (Use the value for copper on your periodic table. I will just use an approximate number.)\
1 mol of copper = 63 grams.
1.038 * 10^9 mols of copper = x
1/1.038 * 10^9 = 63/x Cross multiply
x = 1.038 * 10^9 * 63
x = 6.54 * 10^10 grams of copper.
