Answer:
A metabolic pathway
Explanation:
Biologically, a metabolic pathway is a series of chemical reactions in which the end product of a reaction serves as a substrate (or reagent) for the reaction thereafter, the reactions being interdependent with one another. These reactions are catalyzed by enzymes. The metabolic pathways are fundamental for the maintenance of the cell and consequently of the body's homeostasis.
An example of the metabolic pathway can be seen in the above question where glucose is converted to glucose 6-phosphate by hexokinase. Glucose 6-phosphate then serves as a substrate for the enzyme phosphoglucose isomerase, which converts this reagent to fructose 6-phosphate. Fructose 6-phosphate serves as a substrate for phosphofructokinase, which converts fructose 6-phosphate into fructose 1,6-bisphosphate.
Because the elements have not yet then been discovered.
Hope this helps.
Answer:
3.4321229*10^23 molecules.
Explanation:
1 mole of CBr4 contains 6.0221409*10^23 molecules (Avogadro's Number).
The molar mass of this compound is 12.011 + 4(79.904)
= 331.627 g.
So the answer is (189/ 331.627) * 6.0221409*10^23
= 3.4321229*10^23 molecules.
Answer:
The circular path and electron revolves around the nucleus in an atom is called shell or orbit.
Hey there!
A ) PO₄³⁻
The element exhibits resonance (4 times) as there is a double bondwith 1 oxygen and a single with the other 3 oxygen. This switchesin each resonance structure. (I know its weird b/c I leaves Phosphorus with 10 electrons surrounding it)
b) SO₄²⁻
Sulfur is the central atom ,double bond 2 oxygens so that they can only have 4 valence electrons ( the little dots around the oxygen ) ,single bond 2 oxygens ( So that they have 6 valence electrons )
Formal charges are 0 for the two double bonded oxygens [ 6-6 = 0 ]and 0 for the sulfur [ 6-6=0 ]
But the oxygens are -1 [ 6-7 = -1 ]
Since there are two of them, there is a negative charge of -2
Bracket the whole structure and on the top right of the outside ofthe brackets write 2- and include a - (negative sign) next to eachof the single bonded oxygens
Don't forget there are resonance structures. The double bonds canbe placed around any of the oxygens
Hope that helps!