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Yanka [14]
3 years ago
6

Help;;;;;;;;;;;;;;;;;)

Chemistry
2 answers:
Dmitry [639]3 years ago
7 0

The answer would be 3 cm

Setler [38]3 years ago
3 0
The answer would be 3 cm. you round down to the nearest whole number when it is less than 5. you round up when it is 5 or more.
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How is the structure of atoms altered during fission and fusion?
Dmitriy789 [7]
At first sight it doesn't bode well. The key is in how firmly the protons and neutrons are held together. In the event that an atomic response produces cores that are more firmly bound than the firsts then vitality will be created, if not you should place vitality into make the response happen.
6 0
4 years ago
Proszę napisać wzór kwasu karboksylowego o 7 atomach węgla sumaryczny i strukturalny.
Mice21 [21]

Answer:

Explanation:

Carboxylic acids is a homologous series in which the compounds contain a functional group called the carboxyl group (-COOH). The general molecular formula for carboxylic acids is CnH2n+1COOH. Carboxylic acids contain at least one carboxyl group.

Or in Polish…

Kwasy karboksylowe to homologiczna seria, w której związki zawierają grupę funkcyjną zwaną grupą karboksylową (-COOH). Ogólny wzór cząsteczkowy dla kwasów karboksylowych to CnH2n + 1COOH. Kwasy karboksylowe zawierają co najmniej jedną grupę karboksylową.

8 0
4 years ago
Which compound is a saturated hydrocarbon?<br> A) 2-pentanone B) 2-pentene C) pentane D) pentanal
lesya692 [45]
The answer is the first one because it’s a compound of two words separate when you say it :) hope this helps !
7 0
3 years ago
What is the energy in joules of one photon of<br> microwaveradiation with a wavelength 0.122m?
pentagon [3]

<u>Answer:</u> The energy of photon is 162.93\times 10^{-26}J

<u>Explanation:</u>

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

E = energy of the light  = ?

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of photon = 0.122 m

Putting values in above equation, we get:

E=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{0.122m}\\\\E=162.93\times 10^{-26}J

Hence, the energy of photon is 162.93\times 10^{-26}J

3 0
3 years ago
Which of the following pH numbers indicates a strong alkali?<br> a. 1<br> b. 5<br> c. 7<br> d.) 14
pochemuha

Answer:

1 is the correct answer of the question

7 0
3 years ago
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