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Hoochie [10]
3 years ago
10

There are two laundry trucks One laundry truck visits Roxanne's house every 3 days and another laundry truck visits her neighbor

hood every 4 days. When will both the trucks next visit on the same day ?
Mathematics
1 answer:
stealth61 [152]3 years ago
5 0

Answer:

Evey 12 days  both  of the trucks visit on the same day

Step-by-step explanation:

The LCM of 3 and 4 is 12, because 12 is the smallest number that 3 and 4 are both factors for.

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For a continuous random variable X, P(20 ≤ X ≤ 40) = 0.15 and P(X > 40) = 0.16. Calculate the following probabilities. (Leave
yan [13]

Answer:

For a continuous random variable X, P(20 ≤ X ≤ 40) = 0.15 and P(X > 40) = 0.16.

Step-by-step explanation:

Here, P(x > 40) = 0.16

a). P(x < 40) = 1 - P(x > 40)

                   =  1 - 0.16

                    = 0.84

b). P(x < 20) = 1 - P(x\geq 20)

                    = 1 - {P(20 ≤ X ≤ 40) + P(X > 40)}

                    = 1 - (0.15 + 0.16 )  

                    = 1 - 0.31

                    = 0. 69

c). P(x = 40) = 0; The probability that a continuous variable assume a particular value is zero.

5 0
3 years ago
1
padilas [110]
Answer: B

Trust me I took the test right now
6 0
3 years ago
The quotient of w decreased by 5 and 6<br> write it as an expression
mr_godi [17]

Answer:

W/5-6

Step-by-step explanation:

W/5-6

W/1

5 0
3 years ago
Find the difference between the sum of all even numbers and the sum of all odd numbers from 0 through 1000
Anna007 [38]
The sum is 500 because 1000 split betwwen even and odds are even making 500
3 0
3 years ago
First-order linear differential equations
kkurt [141]

Answer:

(1)\ logy\ =\ -sint\ +\ c

(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

Step-by-step explanation:

1. Given differential equation is

  \dfrac{dy}{dt}+ycost = 0

=>\ \dfrac{dy}{dt}\ =\ -ycost

=>\ \dfrac{dy}{y}\ =\ -cost dt

On integrating both sides, we will have

  \int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}

=>\ logy\ =\ -sint\ +\ c

Hence, the solution of given differential equation can be given by

logy\ =\ -sint\ +\ c.

2. Given differential equation,

    \dfrac{dy}{dt}\ -\ 2ty\ =\ t

=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty

=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})

=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt

On integrating both sides, we will have

   \int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}

=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c

=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

Hence, the solution of given differential equation is

log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

8 0
4 years ago
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