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Hoochie [10]
2 years ago
10

There are two laundry trucks One laundry truck visits Roxanne's house every 3 days and another laundry truck visits her neighbor

hood every 4 days. When will both the trucks next visit on the same day ?
Mathematics
1 answer:
stealth61 [152]2 years ago
5 0

Answer:

Evey 12 days  both  of the trucks visit on the same day

Step-by-step explanation:

The LCM of 3 and 4 is 12, because 12 is the smallest number that 3 and 4 are both factors for.

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adell [148]

Answer:

1. 21

2. 896

3. 20.9

Step-by-step explanation:

Use BODMAS/BIDMAS to solve.

4 0
2 years ago
Does this table represent a proportional relationship?<br><br> Yes<br> No
Contact [7]

no

the table does not represent a proportional relationship.

4 0
3 years ago
Help <br><br><br><br><br><br> I need answers
natali 33 [55]

We can easily work out the meter reading in October. It comes out to be 32347 + 972. So the reading in October must be around 33319.

SO the answer to second question is really easy to figure out too. As we know that one unit costs 14 p we can simply multiply the cost with the number of units consumed.

So for 972 units if we multiply by 14 we get the cost to be around somewhere 13608 p.

6 0
3 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
3 years ago
How many #5 cans of potato salad are required to serve 210 people if each can has 3 pounds 8 ounces of potato salad and each ser
9966 [12]
210 times 5 then divided by 3.8
so rounding up, 277 cans
5 0
3 years ago
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