work shown above! basically each coordinate is opposite so the new coordinates would be A(0,-3) B(-2,4) C(4,6)
Answer:

Step-by-step explanation:
Given
![A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%266%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D)
Required
Determine the determinant
For a two by two matrix, A such that:
![A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
The determinant |A| is:

So, in
![A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%266%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D)
The determinant is:



10.2 ft Ans.
We solve this using geometric series.
A1 = 12 ft
A2 = ?
A3 = 8.67ft
Now, for geomteric progression,


A2 = 10.2 ft
Answer:
36
Step-by-step explanation:
Okay! This question is a very simple one, but without a calculator, your answer could easily vary from others! So, let´s do this one together!
The equation:
0.810x0.00048/0.000400x0.027
Let´s do the top :
0.810 x 0.00048 = 0.0003888
I will leave these numbers the same until the last part, lets not round them.
Bottom:
0.0004 x 0.027 = 0.0000108
And again I am not going to round this number.
Now we can divide!
0.0003888/0.0000108 = 36
I hope this helped!
Let width be x
Length would be x + 3
Area = L * W
Make an equation
(x) * (x+3) = 70
x^2 + 3x = 70
x^2 + 3x - 70 = 0
Quadratic formula
(-3 +/- rt 3^2 - 4 * 1 * (-70))/(2 * 1)
x1 = (-3 + 17)/2, x2 = (-3-17)/2
x = 7, x = -10
Dimension cannot be negative
Solution: width = 7
Length = 10