Question

Hydrogengasand oxygengas react to form water vapor. Suppose you have of and of in a reactor. Calculate the largest amount of that could be produced. Round your answer to the nearest .

Answer 1

The question is incomplete. The complete question is :

Hydrogen $(H_2)$ gas and oxygen $(O_2)$ gas react to form water vapor $(H_2O)$. Suppose you have 11.0 mol of $H_2$ and 13.0 mol of $O_2$ in a reactor. Calculate the largest amount of $H_2O$ that could be produced. Round your answer to the nearest 0.1 mol .

Solution :

The balanced reaction for reaction is :

$2H_2(g) \ \ \ \ + \ \ \ \ \ O_2(g)\ \ \ \rightarrow \ \ \ \ 2H_2O(g)$

11.0                      13.0

11/2                       13/1     (dividing by the co-efficient)

6.5 mol               13 mol    (minimum is limiting reagent as it is completely consumed during the reaction)

Therefore, $H_2$ is limiting reagent. It's stoichiometry decides the product formation amount from equation above it is clear that number of moles for $H_2O$ will be produced = number of moles of $H_2$

                                     = 11.0 mol