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Svetlanka [38]
2 years ago
10

Hydrogengasand oxygengas react to form water vapor. Suppose you have of and of in a reactor. Calculate the largest amount of tha

t could be produced. Round your answer to the nearest .
Chemistry
1 answer:
bezimeni [28]2 years ago
3 0

The question is incomplete. The complete question is :

Hydrogen (H_2) gas and oxygen (O_2) gas react to form water vapor (H_2O). Suppose you have 11.0 mol of H_2 and 13.0 mol of O_2 in a reactor. Calculate the largest amount of H_2O that could be produced. Round your answer to the nearest 0.1 mol .

Solution :

The balanced reaction for reaction is :

$2H_2(g) \ \ \ \ + \ \ \ \  \ O_2(g)\ \ \  \rightarrow \ \ \ \ 2H_2O(g)$

11.0                      13.0

11/2                       13/1     (dividing by the co-efficient)

6.5 mol               13 mol    (minimum is limiting reagent as it is completely consumed during the reaction)

Therefore, H_2 is limiting reagent. It's stoichiometry decides the product formation amount from equation above it is clear that number of moles for H_2O will be produced = number of moles of H_2

                                     = 11.0 mol

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MatroZZZ [7]

Answer:

Mechanism A and B are consistent with observed rate law

Mechanism A is consistent with the observation of J. H. Sullivan

Explanation:

In a mechanism of a reaction, the rate is determinated by the slow step of the mechanism.

In the proposed mechanisms:

Mechanism A

(1) H2(g)+I2(g)→2HI(g)(one-step reaction)

Mechanism B

(1) I2(g)⇄2I(g)(fast, equilibrium)

(2) H2(g)+2I(g)→2HI(g) (slow)

Mechanism C

(1) I2(g) ⇄ 2I(g)(fast, equilibrium)

(2) I(g)+H2(g) ⇄ HI(g)+H(g) (slow)

(3) H(g)+I(g)→HI(g) (fast)

The rate laws are:

A: rate = k₁ [H2] [I2]

B: rate = k₂ [H2] [I]²

As:

K-1 [I]² = K1 [I2]:

rate = k' [H2] [I2]

<em>Where K' = K1 * K2</em>

C: rate = k₁ [H2] [I]

As:

K-1 [I]² = K1 [I2]:

rate = k' [H2] [I2]^1/2

Thus, just <em>mechanism A and B are consistent with observed rate law</em>

In the equilibrium of B, you can see the I-I bond is broken in a fast equilibrium (That means the rupture of the bond is not a determinating step in the reaction), but in mechanism A, the fast rupture of I-I bond could increase in a big way the rate of the reaction. Thus, just <em>mechanism A is consistent with the observation of J. H. Sullivan</em>

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3 years ago
Herbie left his house at 3:30 p.m. and arrived at Kit’s house at 5:00 p.m. The two boys live 7 miles apart. What was Herbie’s av
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Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose they take t minutes to meet each other.

Distance covered by first friend in t minutes, = 0.2 *t=0.2∗t

Distance covered by second friend in t minutes , =0.15 *t=0.15∗t

Total distance is given as 7, so

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0.35 t = 70.35t=7

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means after 20minutes they will meet.

SO. the average speed is 10m: Answer

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The question is incomplete, complete question is:

Study this chemical reaction:

FeSO_4 (aq) + Zn (s)\rightarrow Fe (s) + ZnSO_4 (aq)

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Explanation:

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X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

FeSO_4 (aq) + Zn (s) \rightarrow Fe (s) + ZnSO_4 (aq)

In the given reaction, iron(II) ions are getting reduced and zinc metal is getting oxidized to zinc(II) ions.

Oxidation :

Zn(s)\rightarrow Zn^{2+}+2e^-

Reduction ;

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